5x2y(5 + 20y)
10xy(x + 15y)
10x2(y + 25)
The expression 10x^2y + 25x^2 is an algebraic expression, and the equivalent expression of 10x^2y + 25x^2 is 5x^2(2y + 5)
Equivalent expressions are expressions that have equal values, when evaluated
The expression is given as;
10x^2y + 25x^2
Factor out 5x^2
10x^2y + 25x^2 = 5x^2(2y + 5)
The above means that the equivalent expression of 10x^2y + 25x^2 is 5x^2(2y + 5)
Read more about equivalent expressions at:
x = cm
2. What are the values of the trigonometric ratios for this triangle?
Drag the answer into the box to match each ratio.
sinθ-----
cosθ-----
tanθ-----
OPTIONS YOU CAN DRAG
5/4
3/4
3/5
4/3
4/5
5/3
3. What is the value of x in this triangle?
Enter your answer as a decimal in the box. Round only your final answer to the nearest hundredth.
x = °
4. What is the value of θ for the acute angle in a right triangle?
sin(θ)=cos(58°)
Enter your answer in the box.
θ= °
5. A party tent is used for an outdoor event. Ropes of equal length support each tent pole. The angle the rope makes with the floor is 55°.
What is the height of each pole?
Enter your answer in the box. Round only your final answer to the nearest tenth.
6. What is the exact value of sin 60° ?
Enter your answer, as a simplified fraction, in the box.
Answer: Took the test correct :)
Step-by-step explanation:Problem 1
cos(angle) = adjacent/hypotenuse
cos(18) = x/25
25*cos(18) = x
x = 25*cos(18)
x = 23.7764129073789
x = 23.78
Answer: x = 23.78
=====================================================
Problem 2
theta = greek letter that looks like a "zero" or the letter O with a horizontal line through it
With the reference angle of theta, the opposite side is 3. This side is the leg furthest from the angle theta. In contrast, the side 4 is the closest leg to theta. The longest side 5 is the hypotenuse. The hypotenuse is always the lonest side
sin(theta) = opposite/hypotenuse
sin(theta) = 3/5
cos(theta) = adjacent/hypotenuse
cos(theta) = 4/5
tan(theta) = opposite/adjacent
tan(theta) = 3/4
---------------------------
In summary:
sin(theta) = 3/5
cos(theta) = 4/5
tan(theta) = 3/4
=====================================================
Problem 3
cos(angle) = adjacent/hypotenuse
cos(x) = 15/29
x = arccos(15/29) .... inverse cosine or cos^(-1) also works
x = 58.852610078491
x = 58.85
Answer: x = 58.85
=====================================================
Problem 4
The rule we'll use is
sin(x) = cos(90-x)
sin(theta) = cos(90-theta)
cos(90-theta) = cos(58)
90 - theta = 58
90 - theta+theta = 58+theta
90 = 58+theta
90-58 = 58+theta-58
32 = theta
theta = 32
Answer: 32
=====================================================
Problem 5
x = height of pole
the vertical side is the side we want, which is the opposite side compared to the angle 55 degrees
sin(angle) = opposite/hypotenuse
sin(55) = x/25
25*sin(55) = x
x = 25*sin(55)
x = 20.4788011072248
x = 20.5
Each pole is roughly 20.5 feet tall.
=====================================================
Problem 6
The exact value is the fraction sqrt(3)/2 which can be written as \frac{\sqrt{3}}{2}
"sqrt" is shorhand for "square root"
Read more on Brainly.com - brainly.com/question/6282766#readmore
Given :
Sugar required for 2 1/2 = 5/2 dozen of cookies is 1 1/4 = 5/4 cups.
To Find :
How many cups of sugar does she need to make the cookies for her party.
Solution :
Let, cups of sugar required to make cookies for her party is x.
So,
Therefore, 1/2 cup of cookies is required to make 1 dozen cookies.
Hence, this is the required solution.
Answer: 25/8
Step-by-step explanation:
We would first turn 2 1/2 and 1 1/4 into an improper fraction.
That leaves us with 5/2 and 5/4.
Then, because she needs to make 5/2 dozen cookies and needs 5/4 cups of sugar for every batch, we would multiply 5/2 and 5/4 together.
Therefore x, or the amount of sugar she needs, is 25/8
f(x) = 9x - 8