Answer:
Step-by-step explanation:
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Answer:
Step-by-step explanation:
add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.
The easiest way to compare fractions is by having a common denominator for both fractions.
This is because, when the denominator is the same in both fractions, we will simply compare the numerators and the greater fraction will be the one having greater numerator
Part 1:
The first given fraction is
The second given fraction is
We can make the denominator in the second one equal to 12 by multiplying it by 4.
However, to preserve the value of the fraction, we will multiply it by
This will give us:
* =
Now, the two fractions became and
The denominator is the same, so we will compare numerators.
Since 7 is greater than 4, therefore:
is the greater fraction
Part 2:
The first given fraction is
The second given fraction is
We can make the denominator in the second one equal to 12 by multiplying it by 4.
However, to preserve the value of the fraction, we will multiply it by
This will give us:
* =
Now, the two fractions became and
The denominator is the same, so we will compare numerators.
Since 8 is greater than 7, therefore:
is the greater fraction
Hope this helps :)
The required possible width for the sandbox is w ≤ 13 feet.
Inequality can be defined as the relation of the equation containing the symbol of ( ≤, ≥, <, >) instead of the equal sign in an equation.
Let w be the width of the sandbox in feet.
According to the problem, the length of the sandbox is 4 feet longer than the width, so the length can be represented as w + 4.
To find the amount of wood needed to frame the sandbox, we need to find the perimeter of the sandbox, which is the sum of the lengths of all four sides. Since there are two sides of width w and two sides of length w + 4, the perimeter of the sandbox is:
Perimeter = 2w + 2(w + 4) = 4w + 8
The problem states that Jimmy can use no more than 60 feet of wood, so we can write an inequality that represents this constraint:
4w + 8 ≤ 60
Simplifying this inequality, we get:
4w ≤ 52
w ≤ 13
Therefore, a possible width for the sandbox is w ≤ 13 feet.
Learn more about inequality here:
#SPJ3
Checking with Addition:
Let x, y be two whole numbers.
Then, x + y is definitely a whole number.
So, the set of whole numbers is closed under addition.
Checking with Subtraction:
Let x, y be two whole numbers.
Then, x - y may or may not be a whole number.
For example, if we take 3 and 2,
3 - 2 = 1 is a whole number but if we take 2 and 5, then
2 - 5 = -3 is not a whole number.
So, the set of whole numbers is not closed under subtraction.
Checking with Multiplication:
Let x, y be two whole numbers.
Then, x × y is definitely a whole number.
So, the set of whole numbers is closed under multiplication.
Checking with Division:
Let x, y be two whole numbers.
Then, x / y may or may not be a whole number.
For example, if we take 6 and 3,
6/3 = 2 is a whole number.
But, if we take 4 and 5,
4/5 is not a whole number.
So, the set of whole numbers is not closed under division.