ox is 6 times the weight of tiny, yet tiny can lift ox even when he's holding 80 pounds. tiny is holding up 410 pounds right now (ox plus 80 lbs). How much does tiny weigh.

Answers

Answer 1
Answer:

Answer:

55

Step-by-step explanation:

Find the weight of OX:

If Tiny is carrying 410 pounds, 80 of which are not Ox, then subtract the 80 from the 410.

410-80=330

Now divide the weight of Ox by six, since he weighs six times more than Tiny.

330/6=55

Therefore Tiny is 55 Pounds.

I hope this helps!!


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Find the GCF of each expression. Then factor the expression. 25b^2 - 20b

Answers

Hello!

The prime factors of these two numbres are :

25b^2 = 5^2* b^2\n 20b = 5* 2^2 * b

The GCF can be calculated by multiplying common primes factors :
5* b = 5b

So the GCF is 5b and the expression can be factored this way :
25b^2 - 20b = 5b* 5b - 4* 5b = 5b\left(5b-4\right)

Which number can be added to a rational number to explain that the sum of rational number and a irrational number is irrational?A) -8
B) 2 1/6
C) 5
D) 27

Answers

Answer:

Step-by-step explanation:

5

is correct.  5

cannot be expressed as a fraction. A rational number is any number that can be expressed as the quotient or fraction p/q of two integers, with the denominator q not equal to zero.

I am not sure this is right, but I would say A

1x2(I572535x789)+345678x89/56

Answers

I searched it up, and this is what it showed, hope it helps

45% of the beads in a box are blue. if there are 36 blue beads in the box, how many beads are there altogether ?

Answers

Breaking down the numbers shows that if 45% is 36 beads, then 5% is 4 beads (divide by 9). Then multiply 5% by 20 (to get 100%) and 4 beads by 20 (distributive property) to have 80 beads. 
36÷0.45=80
There are 80 beads altogether

Find the area of the triangle

Answers

Hello!

To find the area of a triangle, first multiply the base by the height. Afterwards, divide the product by 2.

Base: The bottom side of the triangle.
Height: The distance from the bottom to the top of the triangle.

Base = 13
Height = 18.2

13 × 18.2 = 236.6

Now we do the final step, which is to divide by 2.

236.6 ÷ 2 = 118.3

118.3 is your answer.

But why do we divide the product of the base and the height by 2? This is because a triangle is recognized as half of a rectangle/square.

:)
I think it should be 118.3 the equation is base times height divided by two equals the area

Andrew has a new 3 ft wide bookcase with two shelves, each 15 in. in high. he plans to store his CD’s on the shelves, using new CD racks. Each CD rack is 17 in. wide and 7 in. high, and holds three stacks of 12 CDsWill Andrew have enough room for his 250 CD’s in the bookcase if he uses the two shelves inside the book case it doesn’t put any CDs on top of it? how many CDs will he be able to store?

Answers

Answer: He will not have enough room

Step-by-step explanation: To determine if Andrew has enough room for his 250 CDs on the two shelves inside the bookcase, we need to calculate how many CD racks can fit on each shelf and how many CDs each of these racks can hold.

The bookcase is 3 ft wide, which is equivalent to 36 inches. Each shelf is 15 inches high. Therefore, the available space for CD racks on each shelf is 36 inches in width and 15 inches in height.

Each CD rack is 17 inches wide and 7 inches high. To calculate how many racks can fit on each shelf, we can use the following formula:

Number of racks on a shelf = (Width of shelf) / (Width of CD rack)

Number of racks on a shelf = 36 inches / 17 inches ≈ 2.12 (round down to 2, as you can't have a fraction of a rack)

Now, let's calculate how many CDs each of these racks can hold. Each CD rack can hold three stacks of 12 CDs each, for a total of 3 x 12 = 36 CDs.

So, on each shelf, Andrew can fit 2 CD racks, and each rack can hold 36 CDs. Therefore, each shelf can store 2 x 36 = 72 CDs.

Since Andrew has two shelves, he can store a total of 2 x 72 = 144 CDs in the bookcase.

So, he will be able to store 144 CDs in the bookcase, which is less than his 250 CDs. Therefore, he won't have enough room for all his 250 CDs in the bookcase, and he will need additional storage for the remaining CDs.