Answer:
55
Step-by-step explanation:
Find the weight of OX:
If Tiny is carrying 410 pounds, 80 of which are not Ox, then subtract the 80 from the 410.
410-80=330
Now divide the weight of Ox by six, since he weighs six times more than Tiny.
330/6=55
Therefore Tiny is 55 Pounds.
I hope this helps!!
B) 2 1/6
C) 5
D) 27
Answer:
Step-by-step explanation:
5
is correct. 5
cannot be expressed as a fraction. A rational number is any number that can be expressed as the quotient or fraction p/q of two integers, with the denominator q not equal to zero.
Answer: He will not have enough room
Step-by-step explanation: To determine if Andrew has enough room for his 250 CDs on the two shelves inside the bookcase, we need to calculate how many CD racks can fit on each shelf and how many CDs each of these racks can hold.
The bookcase is 3 ft wide, which is equivalent to 36 inches. Each shelf is 15 inches high. Therefore, the available space for CD racks on each shelf is 36 inches in width and 15 inches in height.
Each CD rack is 17 inches wide and 7 inches high. To calculate how many racks can fit on each shelf, we can use the following formula:
Number of racks on a shelf = (Width of shelf) / (Width of CD rack)
Number of racks on a shelf = 36 inches / 17 inches ≈ 2.12 (round down to 2, as you can't have a fraction of a rack)
Now, let's calculate how many CDs each of these racks can hold. Each CD rack can hold three stacks of 12 CDs each, for a total of 3 x 12 = 36 CDs.
So, on each shelf, Andrew can fit 2 CD racks, and each rack can hold 36 CDs. Therefore, each shelf can store 2 x 36 = 72 CDs.
Since Andrew has two shelves, he can store a total of 2 x 72 = 144 CDs in the bookcase.
So, he will be able to store 144 CDs in the bookcase, which is less than his 250 CDs. Therefore, he won't have enough room for all his 250 CDs in the bookcase, and he will need additional storage for the remaining CDs.