The vertices of a pre-image are located at the points (-6,3), (0,0), and (3,6). The end image triangle has coordinates of (-2,1), (0,0), and (1, 2). What type of dilation is it?

A: Expansion
B: Contraction
C: Rotation
D: Diagram

Answers

Answer 1

Answer: The correct answer for the question that is being presented above is this one: "B: Contraction." The vertices of a pre-image are located at the points (-6,3), (0,0), and (3,6). The end image triangle has coordinates of (-2,1), (0,0), and (1, 2). The dilation is B: Contraction

Answer 2

Answer:

Answer:

Option B. contraction

Step-by-step explanation:

The vertices of a pre-image are located at the points (-6, 3), (0, 0), and (3, 6).

The end image triangle has the vertices at (-2, 1), (0, 0), and (1, 2).

Here we can see that one point (0, 0) is common in both the triangles and rest two vertices in end image are changed from the pre-image.

Now we find the ratio of x and y coordinates from end and pre-image we find a ratio of $(-2)/(-6)=1:3$ in x-coordinates.

similarly for y coordinates $(1)/(3)=1:3$ .

Now we can say that there is a contraction in the vertices of end image about the origin (0, 0).

Therefore Option B. Contraction is the correct option.

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Answers

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Answers

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