one side of a square is 10 units.Which is greater,the number of square units for the area or the number of units for the perimeter

Answers

Answer 1
Answer: The number of square units for the area is...

a = length × width
A = 10 × 10 = 100 units ^2

The number of units for perimeter is...

perimeter = 4 × length
perimeter = 40 units

The number of square units for area is larger.

*note - Since we have a square, we know all side Lengths are the same.

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Pls help! will give brainliest

Answers

1= 4
2= I THINK c+3
3=18

PLEASE ANSWER ASAP I WILL MARK BRAINLY

Answers

Answer:

multiplication property of equality

Step-by-step explanation:

Since we are multiplying by the same amount on each side, we are using the multiplication property of equality

Answer: Multiplication Property of Equality

Step-by-step explanation:

This property states that while simplifying an expression, you can multiply both sides of the equation by any number, and it will stay true.  This property is useful here, because multiplying a fraction by its reciprocal = 1, so the expression would become 1x=-128.

Hope it helps <3

Linda asked the students of her class their hockey scores and recorded the scores in the table shown below:Hockey scores

Score. Number of students
0. 2
1. 1
2. 3
3, 6
4. 2
5. 3
6. 2

Based on the table, what is the mean hockey score?

2.7
2.9
3.2
5.2

Answers

ANSWER

The mean hockey score is 3.2

Step - by - step Explanation

The data given is a frequency distribution table.

The mean is calculated using the formula,

Mean = (\sum \:fx)/(\sum \: f)

We obtain

\sum fx

by multiplying each score by the corresponding number of students and add the products as shown in the picture above

By substitution,

Mean= (60)/(19)

Mean= 3.157

Hence the mean hockey score is 3.2 to the nearest tenth.

Answer: 3.2

Step-by-step explanation:

Mean is sum of values, divided by number of examples.

If we write down score for each student, we will receive a long list of scores:

0,0,1,2,2,2,3,3,3,3,3,3,4,4,5,5,5,6,6

Now let's sum total scores achieved by students:

0+0+1+2+2+2+3+3+3+3+3+3+4+4+5+5+5+6+6 = 60

So sum of our values (scores) is 60.

Number of examples in our case is number of students, so, total number of students is:

2+1+3+6+2+3+2=19

So mean score in this group can be calculated as:

mean

    = total sum / number of examples

    = sum of scores / number of students

    = 60/19

    = 3,158

So closes answer is 3.2.

What is the sum of the first 4 terms of the arithmeticsequence in which the 6th term is 8 and the 10th term
is 13 ?
F. 10.5
G. 14.5
H. 18
J. 21.25
K. 39.5

Answers

a_6=8;\ a_(10)=13\n\na_(10)-a_6=4r\n\n4r=13-8\n4r=5\ \ \ \ /:4\nr=1.25\n\na_1=a_6-5r\na_1=8-5\cdot1.25=8-6.25=1.75\n\nS_4=(2a_1+(4-1)r)/(2)\cdot4=(2a_1+3r)\cdot2=4a_1+6r\n\nS_4=4\cdot1.75+6\cdot1.25=7+7.5=14.5

Final answer:

The sum of the first 4 terms of the arithmetic sequence where the 6th term is 8 and the 10th term is 13 is 14.5.

Explanation:

In an arithmetic sequence, the difference between consecutive terms is constant. This difference is commonly called the common difference. Given that the 6th term is 8 and the 10th term is 13, we can calculate this common difference.

The common difference is (13 - 8) / (10 - 6) = 5 / 4 = 1.25.

The common difference is backward from the 6th term to the first term or we can say the 6th term minus 5 times the common difference will give us the first term. Therefore, the first term is 8 - 5*1.25 = 8 - 6.25 = 1.75.

The sum of the first 4 terms of an arithmetic sequence is given by the formula S = n/2 *[2a + (n-1)*d], where 'n' is the number of terms (in this case 4), 'a' is the first term, and 'd' is the common difference.

Therefore, substituting our known values into the formula gives us: S = 4/2 *[2*1.75 + (4-1)*1.25] = 2*[3.5 + 3.75] = 2*7.25 = 14.5

Learn more about Arithmetic Sequence here:

brainly.com/question/32830972

James started tutoring children several times a week. The first 2 weeks he had to buy tutoring supplies and had losses of $40 and $56. The next three weeks he made a profit of $105, $70, and $140. At the end of the 6 weeks, he had a net profit of $252.

(a) write an equation to find the profit or loss for the 6th week in this situation. Solve your equation. Was there a profit or a loss for that week? Show your work.
(b) What was James's average profit or loss for the 6 weeks? Show your work.
This is on k12, please help me!


Answers

Given:
Week 1 : - 40
Week 2 : - 56
Week 3 : 105
Week 4 :   70
Week 5 : 140
Week 6 : ?

At the end of the 6th week, net profit is 252.

Profit = 105 + 70 + 140 = 315
Loss = 40 + 56 = 96
Net Profit = 315 - 96 = 219
252 - 219 = 33 Profit on Week 6.

Average profit : 252 / 6 = 42 per week

5. WHAT IS THE SOLUTION TO THE SYSTEM?
5x – 2y + z = 0
2x – y + z = 3
3x + 4y = 18

Answers

Answer:

x= 2/5 y - 1/5 z

x= 3/2 + 1/2 y -1/2 z

x = 6 - 4/3 y

Step-by-step explanation:

5x – 2y + z = 0

5x=2y-z

* Moving variables to the right side and changing their signs

* divide both sides by 5

Answer: x= 2/5 y - 1/5 z

2x - y + z = 3

2x = 3 + y - 2

Answer: x= 3/2 + 1/2 y -1/2 z

* move variables to the right sides and change their signs

* divide both sides by 2

3x + 4 y = 18

3x/3 = 18 - 4/3

Answer: x = 6 - 4/3 y

* Move variables to the right side and change its sign

* divide both sides by 3