What is the power of 10 when 0.000028 is written in scientific notation
Answers
For this case, the first thing we must do is define the scientific notation.
We have then:
Scientific notation is a way of writing numbers too big or small in a conventional way.
A number written in scientific notation has the following form:
Where,
m: it is called matinsa
e: it is the order of magnitude
Therefore, for the given number we have that the scientific notation is:
Answer:
the power of 10 when 0.000028 is written in scientific notation is:
-5
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A student want to see what floats better a 1 pound piece of wood with a density of 0.90g/ml or a 10 pound piece of wood with a density 0.90g/ml explain your reasoning
b. The dark lines are at higher energies than the bright lines.
c. The bright lines are at higher energies than the dark lines.
d. You cannot relate the two types of spectra.
Answers
Wouldn't it be neat if an electron falling closer to the nucleus ... emitting a
photon ... actually gave out more energy than it needed to climb to its original
energy level by absorbing a photon ! If there were some miraculous substance
that could do that, we'd have it made.
All we'd need is a pile of it in our basement, with a bright light bulb over the pile,
connected to a tiny hand-crank generator.
Whenever we wanted some energy, like for cooking or heating the house, we'd
switch the light bulb on, point it towards the pile, and give the little generator a
little shove. It wouldn't take much to git 'er going.
The atoms in the pile would absorb some photons, raising their electrons to higher
energy levels. Then the electrons would fall back down to lower energy levels,
releasing more energy than they needed to climb up. We could take that energy,
use some of it to keep the light bulb shining on the pile, and use the extra to heat
the house or run the dishwasher.
The energy an electron absorbs when it climbs to a higher energy level (forming
the atom's absorption spectrum) is precisely identical to the energy it emits when
it falls back to its original level (creating the atom's emission spectrum).
Energy that wasn't either there in the atom to begin with or else pumped
into it from somewhere can't be created there.
You get what you pay for, or, as my grandfather used to say, "For nothing
you get nothing."
Final answer:
The dark absorption lines of an atom's spectrum correspond to the same energies as the bright emission lines. They both reflect energy changes in electron states.
Explanation:
The dark lines of an atom's absorption spectrum are at the same energies as the bright lines of its emission spectrum, therefore the correct answer is a. The bright lines are at the same energies as the dark lines. Absorption spectra are produced when electrons absorb energy and move to a higher energy level, while emission spectra are observed when electrons lose energy and return to a lower energy level.
The dark lines (absorption) and bright lines (emission) coincide because the energy required to move an electron from a lower to higher energy level matches the energy released when an electron drops from a higher to lower state.
Learn more about Absorption and Emission Spectra here:
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Answers
In this question we have given
velocity of missile=1350m/s
angle at which missile is moving=25degree
distance between missile and targets=23500m
angle between target and missile=55degree
time=10.2s
To find the final velocity of missile we will first find the acceleration required
Let x be the horizontal component of distance
x - vertical component of distance
t-time
ax- horizontal component of acceleration
ay-Vertical component of acceleration
Vx-horizontal component of velocity
Vy-Vertical component of velocity
horizontally: x = Vx*t + ½*ax*t²
23500m * cos55.0º = 1350m/s * cos25.0º * 10.20s + ½ * ax * (10.20s)²
ax = 19.2 m/s²
V'x = Vx + ax*t = 1350m/s * cos25.0º + 19.2m/s² * 10.20s = 1419 m/s
similarly vertically:
y = Vy*t + ½*ay*t²
23500m * sin55.0º = 1350m/s * sin25.0º * 10.20s + ½ * ay * (10.20s)²
ay = 258 m/s²
V'y = Vy + ay*t = 1350m/s * sin25.0º + 258m/s² * 10.20s = 3204 m/s
Therefore
V = √(V'x² + V'y²) = 3504 m/s
therefore magnitude of final velocity of missile=3504m/s
Answers
Final answer:
At the peak of its trajectory, the ball's vertical velocity (v1,y) is zero, whereas its horizontal velocity (v1,x) maintains its consistency. The accelerations a1,x and a1,y are 0 and -9.8 m/s² respectively.
Explanation:
The physical concept analyzed here is projectile motion. Considering the trajectory of a ball, we can separate its motion into horizontal and vertical components. At the peak of its trajectory (time t1), the ball's vertical velocity (v1,y) is zero, because it temporarily stops moving upwards before it begins to fall again. However, since there is no acceleration in the horizontal direction (a1,x), the ball keeps moving horizontally with constant velocity (v1,x).
The acceleration in the vertical direction (a1,y) is still the acceleration due to gravity (-9.8 m/s²). This is because even at the peak of the trajectory, the ball is still accelerating downwards. Therefore, the correct answer should include v1,y = 0 m/s, v1,x = consistent value, a1,x = 0 m/s², and a1,y = -9.8 m/s². So the most probable answer is D) 15.0, 0, 0, -9.80, assuming the ball's horizontal velocity is 15 m/s. Please check the exact value of horizontal velocity (v1,x) in the settings of your problem.
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Answers
Here are the following choices:
A) 0.25s
B) 0.40s
C) 2.5s
D) 4.0s
b. upright and larger than the object.
c. inverted and smaller than the object.
d. upright and smaller than the object.
Answers
a. inverted and larger than the object.
A mirror is used to see your own reflection. Earlier in the days, people would use a still water to see their reflection. It is basically used for grooming. Spherical mirrors have been used by earlier mathematicians and physicist to conduct experiments related to geometry.
Penn Foster STudents: d. upright and smaller than the object.