Prime factorization for 58, 2,800, 212, 900

Answers

Answer 1
Answer: The prime factorization for:
- 58 ----> 2, 29
- 2800 ----> 2^4 * 5^2 * 7
- 212 ----> 2*2*53
- 900 ----> 2*2*3*3*5*5
I hope this helped you...

Related Questions

Add the following fractions.3/8 + 5/12 =
Why might algebra tiles not be a good tool to use to factor x2 + 18x + 80? Explain.
Write and solve a formula to find the perimeter of the field exculding the two shooting circles.
I will mark brainliest i need help quick
PLSSSS HELP IF YOU TULRY KNOW THISSS

Helpppppp. (the other one cut out is multiplication property of equality)​

Answers

Answer:

The second step is Distributive Property and the third is Subtraction Property of Equality

Step-by-step explanation:

The 1/2 is being distributed in the second step making the 8x to 4x and the 6 to 3.

The third step involves the subtraction of "x" from the right hand side and the left hand side.

2 pens costs £0.30.
How much would 4 pens cost?

Answers

Answer:

cost of 4 pen is £0.6

Step-by-step explanation:

cost of 2 pen *2= cost of 4 pen

£0.30*2=cost of 4 pen

£0.60=cost of 4 pen

for my hardwork make me barinliest answer

Fifteen times a number subtracted from 80 is 25

Answers

The required number would be 11 / 3 which represents " Fifteen times a number subtracted from 80 is 25".

What are Arithmetic operations?

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions. The operator that performs the arithmetic operation is called the arithmetic operator.

- Subtraction operation: Subtracts the right-hand operand from the left-hand operand.

for example 12 -2 = 10

* Multiplication operation: Multiplies values on either side of the operator

For example 12*2 = 24

To determine the number which is Fifteen times a number subtracted from 80 is 25

Let the number be x.

As per the given condition,

Here the required number would be Fifteen times = 15x and

Then this is subtracted from 80;  80 - 15x

⇒ 80 - 15x = 25

⇒ -15x = 25 - 80

⇒ -15x = -55

⇒ x = -55 / -15

Apply the Division operation, and we get

⇒ x = 11/3

Therefore, the required number would be 11 / 3.

Learn more about Arithmetic operations here:

brainly.com/question/25834626

#SPJ2

Let the number be x.

15 times the number = 15x

This  is subtracted from 80,    80 - 15x

80 - 15x = 25

-15x = 25 - 80

-15x = -55

x = -55 / -15

x = 11/3

So the number is 11 / 3.

Akar akar persaman 3x^2+x-4=0 adalah

Answers

factor (3x+4)(x-1)=0 so 3x+4=0 3x=-4 x=-4/3 x-1=0 x=1 x=1 and -4/3
1 and -4/3 ...........

Which ratio forms a proportion with 16/20

Answers

Answer:

4/5 forms a proportion with 16/20.

Step-by-step explanation:

We are given an rational number as 16/20.

we have to find another rational number which is equivalent to it.

as both 16 and 20 are multiple of 4 we could also represent the ratio 16/20 as:

(16)/(20)=(4 * 4)/(4*5)

we cancel 4 on both the numerator and denominator to get (4)/(5).

Hence,  the ratio (4)/(5) is proportion with (16)/(20).


4/5 is equivalent to the fraction 16/20

Tan^2 A/1+cot^2 A + cot^2 A/1+tan^2 A=sec^2 A cosec^2 A-3

Answers

(tan^2x)/(1+cot^2x)+(cot^2x)/(1+tan^2x)=sec^2x\ cosec^2x-3\n\nL=(tan^2x(1+tan^2x)+cot^2x(1+cot^2x))/((1+cot^2x)(1+tan^2x))=(tan^2x+tan^4x+cot^2x+cot^4x)/(1+tan^2x+cot^2x+tanxcotx)\n\n=(tan^2x+cot^2x+tan^4x+cot^4x)/(1+tan^2x+cot^2x+1)=(tan^2x+2+cot^2x+tan^4x-2+cot^4x)/(tan^2x+cot^2x+2)

=((tanx+cotx)^2+(tan^2x-cot^2x)^2)/((tanx+cotx)^2)=((tanx+cotx)^2)/((tanx+cotx)^2)+((tan^2x-cot^2x)^2)/((tanx+cotx)^2)\n\n=1+((tanx-cotx)^2(tanx+cotx)^2)/((tanx+cotx)^2)=1+(tanx-cotx)^2\n\n=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\n\n=\left((sinx)/(cosx)\right)^2+\left((cosx)/(sinx)\right)^2-1=(sin^2x)/(cos^2x)+(cos^2x)/(sin^2x)-1=(sin^4x+cos^4x)/(sin^2x\ cos^2x)-1

=((sin^2x)^2+2sin^2x\ cos^2x+(cos^2x)^2-2sin^2x\ cos^2x)/(sin^2x\ cos^2x)-1\n\n=((sin^2x+cos^2x)^2-2sin^2x\ cos^2x)/(sin^2x\ cos^2x)-1=(1^2-2sin^2x\ cos^2x)/(sin^2x\ cos^2x)-1\n\n=(1)/(sin^2x\ cos^2x)-(2sin^2x\ cos^2x)/(sin^2x\ cos^2x)-1=(1)/(sin^2x)\cdot(1)/(cos^2x)-2-1\n\n=cosec^2x\cdot sec^2x-3=sec^2x\ cosec^2x-3=R