Answer:
c ≤ -14/17
Step-by-step explanation:
-32c+12 ≤-66c-16
-32c+12-12 ≤-66c-12-12
-32c ≤-66c-28
-32c+66c ≤-66c-28 +66c
34c ≤-28
34c/34 ≤-28/34
Answer:
Hey guys! I got it wrong from the other answer so here is the actual one:
c≤= -14/17
Good luck everyone! :)
The solution is, the 8th term of the arithmetic sequence with a first term of 7 and a common difference of -3 is, a_8 = - 14.
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
For instance, the sequence 5, 7, 9, 11, 13, 15.. . is an arithmetic progression with a common difference of 2.
The nth term of AP : a_n = a + (n – 1) × d
here, we have,
we know that,
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 7 and d = - 3,
thus,
a_8 = 7 + (7 × - 3) = 7 - 21 = - 14
Hence, The solution is, the 8th term of the arithmetic sequence with a first term of 7 and a common difference of -3 is, a_8 = - 14.
To lean more on Arithmetic progression click:
#SPJ2
Answer:
= - 14
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 7 and d = - 3, thus
= 7 + (7 × - 3) = 7 - 21 = - 14