Camilla has a cat that weights 3 pounds her friend Kayla has a dog that weights 9 pounds who pet weights more

Answers

Answer 1

Answer: Kayla's dog weights more because 9 is a bigger number than 3. So if you subtract 9 - 3 you get 6. So Kayla's dog weights 6 more pound than Camilla's cat.

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Whats more 5 miles or 26,300 yards

Answers

26300 is more because 5 miles is almost the same but I had searched up and it said 5 miles is less

26,300 yards is longer because 26,300 yard is equal to 14.94 miles ( 14 or 15 miles)

Latasha earned 18 points on her quiz. If 24 points is equivalent to a score of 100% what two proportions could she use to calculate her percent score?

Answers

Given:
18 points on her quiz
24 points is equivalent to 100%

18 is to 24 or 18/24
x is to 100% or x/100%

18/24 = x/100%

18 * 100% = 24x
1800% = 24x
1800%/24 = x
75% = x

18/24 = 75%/100%
18 * 100% = 24 * 75%
1800% = 1800%

Answer:

Step-by-step explanation:

Given:

18 points on her quiz

24 points is equivalent to 100%

18 is to 24 or 18/24

x is to 100% or x/100%

18/24 = x/100%

18 * 100% = 24x

1800% = 24x

1800%/24 = x

75% = x

18/24 = 75%/100%

18 * 100% = 24 * 75%

1800% = 1800%

colby and jaquan are growing bacteria in an experiment in a laboratory. Colby starts with 50 bacteria in his culture and the number of bacteria doubles every two hours. Jaquan has a different type of bacteria that doubles every three hours. How many bacteria should Jaquan start with so that they have they have the same amount at the end of the day?

Answers

To get started, we will use the general formula for bacteria growth/decay problems:

$A_(f) = A_(i) ( e^(kt) )$

where:
A_{f} = Final amount
A_{i} = Initial amount
k = growth rate constant
t = time

For doubling problems, the general formula can be shortened to:

$kt = ln(2)$

Now, we can use the shortened formula to calculate the growth rate constant of both bacteria:

Colby (1):
$k_(1) = ln(2)/t$
$k_(1) = ln(2)/2 = 0.34657$ per hour

Jaquan (2):
$k_(2) = ln(2)/t$
$k_(2) = ln(2)/3 = 0.23105$ per hour

Using Colby's rate constant, we can use the general formula to calculate for Colby's final amount after 1 day (24 hours).

Note: All units must be constant, so convert day to hours.

$A_(f1) = 50( e^(0.34657(24)))$
$A_(f1) = 204,800$

Remember that the final amount for both bacteria must be the same after 24 hours. Again, using the general formula, we can calculate the initial amount of bacteria that Jaquan needs:

$A_(f2) = 204,800 = A_(i2) ( e^(0.23105(24)) )$
$A_(i2) = 800$

If your pencil is 20 cm long how many millimeters is it

Answers

For this, you have to know the unit conversions. For metric, this is somewhat easier to remember. cm = centimeters. centi means 100th. One way to remember this one is that a cent is 1/100th of a dollar. So also is a centimeter 1/100th of a meter. A millimeter is 1/1000th of a meter. so a centimeter is 10 millimeters.
$(20)/(1) (cm)/(1) * (10)/(1)(millimeters)/(cm) = 200 millimeters$

Therefore the solution is 200 millimeters.

A bookmark is shaped like a rectangle with a semicircle attached at both ends. The rectangle is 12 cm long and 4 cm wide. The diameter of each semicircle is the width of the rectangle. What is the area of bookmark ? Use 3.14 for pie

Answers

So you know that the are of a rectangle is Length x width, so that part is simply 12x4, which =48 sq cm.
To find the area of the two ends of the bookmark, two semicircles make one circle, so you can just find the area of one circle. The formula for the area of a circle is (3.14) x r². Because the diameter of the circle is the same as the width of the rectangle, half of the 4cm is the radius (2cm).
Area of Circle= (3.14)x(2²)=12.56 cm sq.
Total area = Area of rectangle + Area of Circle
TA= 48 + 12.56
TA= 60.56 sq cm

Bonnie and some friends went to an amusement park. They bought rve of thesame lunches and 3 desserts and spent a total of $60.25 on the food. Eachdessert costs $5.25 less than one of the lunches.a. Detine a variable: Write an equation that can be used to find the cost oflunch.b. Solve the equation to find the cost of a lunch.en5.2

Answers

Let the variable be the cost of the lunch: x

so they bought 5 lunches: 5x
deserts are cheaper than lunches; they cost:
x-5.25
So together they paid:
5x+3*(x-5.25)=60.25

(we know how much they paid, so we can make an equation)

Let's remove the bracket:
5x+3*x-15.75=60.25

8x-15.75=60.25//we add 15.75 to both sides:
8x=76
and divide by 8:
x=9.5

So each lunch costs 9.5 dollars!

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