Pentane burns in plenty of air: CO₂ and H₂O is produced.
C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O
Pentane burns in limited amount of air: CO or even C is produced along with H₂O.
2 C₅H₁₂ + 11 O₂ → 10 CO + 12 H₂O
Pentane is a hydrocarbon. There are five carbon atoms in each of its molecule. Its molecular formula will be C₅H₁₂.
Hydrocarbon fuels burn to produce CO₂ when there's plenty of air.
? C₅H₁₂ + ? O₂ → ? CO₂ + ? H₂O
1 C₅H₁₂ + ? O₂ → ? CO₂ + ? H₂O
1 C₅H₁₂ + ? O₂ → 5CO₂ + ? H₂O
1C₅H₁₂ + ? O₂ → 5CO₂ + 6 H₂O
1C₅H₁₂ + 8 O₂ → 5CO₂ + 6 H₂O
1 C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O
Hydrocarbon fuels burn to produce H₂O and CO when there's a limited supply of air. C (soot) might also be produced. Assuming that only CO is produced. Try to balance the equation using the same method.
1 C₅H₁₂ + 11/2 O₂ → 5 CO + 6 H₂O
2 C₅H₁₂ + 11 O₂ → 10 CO + 12 H₂O
Less O₂ is consumed for each mole of C₅H₁₂.
Consider: What would be the balanced equation when only C is produced?
"Products and effects of combustion", GCSE Chemistry (Single Science), BBC Bitesize.
(2) nitrogen (4) oxygen