Answer:
The last one is B.
Step-by-step explanation:
The shapes having area of 6 square units and a perimeter of 12 units is shown below.
The total space occupied by a flat (2-D) surface or the shape of an object is defined as its area. The area of a plane figure is the space enclosed by its boundary. The number of unit squares that cover the surface of a closed form is the figure's area.
The perimeter of a shape is the distance around its edge.
We have the figure attached below.
First, the Area of First Figure
= 6 x 1
= 6 unit
and, Perimeter of First Figure
= 1 + 1 + 1 + 1 + 1 + 1+ 1 +1 + 1 +1 +1 + 1
= 12 unit
Second, the Area of Second Figure
= 6 x 1
= 6 unit
and, Perimeter of Second Figure
= 2 + 1 + 2+ 2 + 4+ 1
= 12 unit
Learn more about Area and Perimeter here:
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The problem evaluates the expression 47 + 2d, by substituting d = 3. This results in 47 + 2*3, which simplifies to 47 + 6. The final answer is 53.
This is a simple algebraic problem. The expression you're asked to evaluate is
47 + 2d
and you've been told to substitute
d = 3
. So substituting, we get 47 + 2*(3). The multiplication operation takes precedence according to the order of operations, so next we calculate 2*3 to get 6. Adding this to 47 gives us 53. Therefore, the solution to 47 + 2d, for d = 3, is 53.
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Answer:
Explanation:
Rewrite Equation:
47 + (2 · 3)
Solve:
Follow PEMDAS Order Of Operations
2 · 3 = 6
= 47 + 6
Add
47 + 6 = 53
= 53
Mordancy.
A. 10 cm
B. 11 cm
C. 9 cm
D. 8 cm
Answer:
Sphere Volume = (4/3) * PI * radius^3
radius = cube root (Sphere Volume) / (4/3)*PI
radius = cube root (5,600) / (4/3)*PI
radius = 11.016 cm
radius = 11 cm (rounded)
Answer is B
Step-by-step explanation:
one-fourth
one-third
four-ninths
5)The two numbers rolled can be added to get a sum. Find P(sum is even).
one-fourth
fifteen over thirty-six
one-half
three-fourths