Nth term for this sequence 45,40,35,30

Answers

Answer 1

Answer: (n-5)+45
where n is the number, you always take away 5 and you add 45 because that is the first number of the sequence

Answer 2

Answer:

Final answer:

The nth term for the given arithmetic sequence 45, 40, 35, 30 is 50 - 5n.

Explanation:

The given sequence

45, 40, 35, 30

is an arithmetic sequence with a common difference of -5.

The general formula for the nth term (an) of an arithmetic sequence is:

an = a1 + (n-1)d

where a1 is the first term and d is the common difference.

Plugging in the values from the given sequence, we can find the nth term:

an = 45 + (n-1)(-5)

Simplifying further, we get:

an = 50 - 5n

So, the nth term of the sequence is 50 - 5n.

Learn more about Arithmetic Sequence here:

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a chess player played 20 games total. if he won 2 of the games, what is the ratio of games he lost to games he won?

Answers

$20-2=18\n\sf\nSo,~ he~ lost~ 18~ games.\n\ngames~ lost:games~ won\n\nThe~ ratio ~is \n18:2\n\nWhich~ can~ be~ simplified ~to\n9:1$

1. Find the ratio of the Chess player in where he played a total of 20 games and won 2 of the games.
Ratio is considered as the quantitative relationship between to numbers that show the value of both sides.
Now, in the chess game, there are 20 games in all and he won 2 games. To get the ratio of his lose and win, simply subtract 2 from 20
=> 20 -2 = 18
thus, the ratio of the chess game is
=> 18 : 2
=> 18 is the lose
=> 2 is the win.

2 + 2 + 6 / 9 ^2 + 600 + 2400 + 45 - 42

Answers

4 + 6/81 + 3000 + 3 = 3007 + 2/27 = 3007 + 0.07 = 3007.07;

Answer:

Step-by-step explanation:

3000.07

Mindy and Troy combined ate 9 pieces of the wedding cake. Mindy ate 3 pieces of cake and Troy had 1/4 of the total cake.. Write an equation to determine how many pieces of cake (c) there were in total.

Answers

M + T = 9
M = 3
T = 6
Equation:
1/4 c = 6
c = 6 * 4 = 24

9-3=6
Troy ate 6 pieces of the cake
1/4 of the cake equal 6 pieces of the cake
There are 6x4=24 pieces of the cake in total.

solve using the substitution and elimination method

3a-12b=9

4a-5b=3

can someone please help?

Answers

3a-12b=9 => a = 4b + 3; but, 4a-5b=3 => 4(4b + 3) -5b = 3 => 11b = -9 => b = -9/11 => a = -36/11 + 3 = -3/11;

Answer:6969

Step-by-step explanation:

Its the best answer

If G(t)=(3t-5)^2 + 4t-1, find each of the following: A.G(a) B.G(a + 2)

Answers

g(a)=(3a-5)^2+4t-1=9a^2-26x+24
g(a+2)=(3(a+2)-5)^2+4(a+2)-1=9a^2+10x+8

Solve the system by graphing. Write the solution as an ordered pair. y = 1/3x + 2 y = –x – 2Help me please....I need good grades

Answers

ANSWER

The solution is where the two graphs intersect, which is
$(-3,1).$

EXPLANATION

The given system of equations are
$y = (1)/(3) x + 2$
and

$y = - x - 2$

We need to graph the two equations.

Let us graph

$y = (1)/(3) x + 2$
first.

We need at least two points.

You can choose any appropriate value for x and solve for y. Choosing zero makes our working easier. So let us plot the intercepts.

When
$x = 0$

$\Rightarrow \: y = (1)/(3) (0) + 2$

$\Rightarrow y = 0 + 2$

$\Rightarrow y = 2$

So this gives us the ordered pair,

$(0,2)$

When
$y = 0$
we get,

$0= (1)/(3) x + 2$

$\Rightarrow \: - 2 = (1)/(3) x$

$\Rightarrow \: - 2 * 3= x$

$\Rightarrow \: -6= x$
This also gives the ordered pair

$(-6,0).$

We plot these two points and draw a straight line through them to obtain the blue graph in the attachment.

For the second line

We again find the intercepts and plot them.

When
$x = 0$

$y = - 0 - 2$

$\Rightarrow \: y = - 2$

This gives the ordered pair

$(0,-2)$

Also, when
$y = 0$

then we have,

$0 = - x - 2$

$2 = - x$

$x = - 2$

Then we again have the ordered pair,

$(-2,0)$

We plot these two points on the same graph sheet to obtain the red graph above.

The intersection of the two lines is
$(-3,1)$

You will get good grades so don't worry much.

Answer:

jh24

Step-by-step explanation:

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