What effect does the presence of dissolved sodium fluoride have on the dissociation equilibrium of hydrofluoric acid? (select all three that apply)...The percent dissociation of HF is reduced by the presence of dissolved NaF.
THe pH of the solution containing NaF and HF would be higher than that of a solution of HF only.
The presence of NaF drives the reaction towards the HF side to reach equilibrium.
The concentration of H+ is higher in an HF solution containing NaF.
The pH of the solution containing NaF and HF would be lower than that of a solution of HF only.
The presence of the dissolved NaF does not affect the HF equilibrium reaction nor the equilibrium concentrations.

Answers

Answer 1
Answer: The correct answer for the question that is being presented above is this one: "The pH of the solution containing NaF and HF would be lower than that of a solution of HF only.; THe pH of the solution containing NaF and HF would be higher than that of a solution of HF only."

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How many grams are in 2.4 moles of sulfur?

Answers

According to the mole concept, there are 76.94 g in 2.4 moles of sulfur atoms.

What is a mole?

Mole is defined as the unit of amount of substance . It is the quantity measure of amount of substance of how many elementary particles are present in a given substance.

It is defined as exactly 6.022×10²³ elementary entities. The elementary entity can be a molecule, atom ion depending on the type of substance. Amount of elementary entities in a mole is called as Avogadro's number.

It is widely used in chemistry as a suitable way for expressing amounts of reactants and products.For the practical purposes, mass of one mole of compound in grams is approximately equal to mass of one molecule of compound measured in Daltons. Molar mass has units of gram per mole . In case of molecules, where molar mass  in grams present in one mole  of atoms is its atomic mass.

Mass is found out by number of moles by formula , mass=number of moles×molar mass

Substitution in above formula gives, mass=2.4×32.06=76.94 g

Thus, there are 76.94 g in 2.4 moles of sulfur.

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Use the equation 
Given molesX Molar Mass(g)/1 mol= Mass in grams
2.4 moles X 32.065/1
76.96 Grams :)

The blue color of the sky results from the scattering of sunlight by molecules in the air. The blue light has a frequency of about 7.03 × 1014 Hz. Calculate the wavelength (in nm) associated with this radiation, and calculate the energy (in joules) of a single photon associated with this frequency. Enter your answers in scientific notation.

Answers

Answer:

λ = 426.7 nm

E = 4.66 x 10⁻¹⁹ J

Explanation:

The equation of frequency is:

f = v / λ

v: velocity

λ: wavelength

λ = v / f

λ = 3 x 10⁸ m.s⁻¹ / 7.03 x 10¹⁴ Hz

λ = 426.7 nm

The energy of a single photon is

E = hf

h: Plank's constant = 6.63 x 10⁻³⁴ m²kgs⁻¹

E =  6.63 x 10⁻³⁴ m²kgs⁻¹ x 7.03 x 10¹⁴ Hz

E = 4.66 x 10⁻¹⁹ J

Why is HBrO a weaker acid than HBrO3? A. The HO bond in HBrO is less polar than the HO bond in HBrO3 B. The HO bond in HBrO is more polar than the HO bond in HBrO3 C. The HBr bond in HBro is weaker than the HBr in HBrO3 D. The HBr bond in HBrO is stronger than the HBr bond in HBrO3 E. The HO bond in HBrO is weaker than the HO bond in HBrO3

Answers

Ans:  A)

HBrO and HBrO₃ are oxyacids where the acidic strength increases with the increase in the number of atoms attached to the central atom.

In both acids, oxygen is the most electronegative atom. In HBrO, the B atom is linked to only one O atom. In contrast, there are 3 electronegative O atoms surrounding the central B atom in HBrO₃ which would make the OH bond more polar and easily accessible. Thus, HBrO₃ tends to lose a proton readily than HBrO making the former more acidic.

HBrO is a weaker acid than HBrO3 because the H-O bond in HBrO is less polar than the H-O bond in HBrO3. In a series of oxyacids with similar formulas, the higher the electronegativity of the central atom, the stronger is the attraction of the central atom for the electrons of the oxygen(s), making the acid stronger.

The acid strength of HBrO is weaker than HBrO3 because the H-O bond in HBrO is less polar than the H-O bond in HBrO3 (Option A). In a series of oxyacids with similar formulas, the higher the electronegativity of the central atom, the stronger is the attraction of the central atom for the electrons of the oxygen(s). This stronger attraction of oxygen for the electrons in the O-H bond makes the hydrogen more easily released, resulting in a stronger acid (Option E). Therefore, HBrO3 is a stronger acid than HBrO.

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A 10.0-gram sample of which element has the smallest volume at STP?(1) aluminum (3) titanium
(2) magnesium (4) zinc

Answers

Since all of these elements are under the same conditions, volume only varies based on the number of atoms present. You can find the number of atoms in a given sample by dividing the weight of the sample by the molar mass.

Aluminum has a molar mass of 26.9 so 10/26.9 = .371 moles

go on to get Ti= 10 /  47.88 =.209 moles

Mg = 10.0 / 24.3 = 0.412 moles

Zn = 10 / 65.37 = .153 moles

Since there are less moles of Zn, it has the smaller volume at STP than the other elements.

What is the charge of an electron? Positive one

Positive two

Negative one

Negative two

Answers

Answer:

The correct answer is the c = negative one

Explanation:

Hello! Let's solve this!

The electron is a particle that is part of the atom. The atom is also made up of neutrons and protons. Protons have a positive charge and are located in the nucleus. Neutrons have a neutral charge and are also located in the nucleus.

The electron has a negative charge and travels its orbitals around the nucleus.

The correct answer is the c = negative one

The charge on an electron is negative one

Which electrons are removed first when forming cations of Period 4 transition elements?

Answers

Electrons are always removed from the valence electron shells and from the valence orbitals within the shell when forming a cation. For example, Cr has a electronic configuration of 1s2 2s2 2p6 3s2 3p6 3d5 4s1
When forming the ion Cr3+, the new electronic configuration will be 1s2 2s2 2p6 3s2 3p6 3d3. We can see that 3 electrons are removed from the valence shell following the order of the highest energy orbitals to lower energy.