In this question, we create a system of inequalities to describe the possible number of hours and distance you may have to drive. It is not possible to have driven 160 miles.
Part A:
Let t represent the number of hours you drive and d represent the distance you drive.
The constraints for the number of hours are: 0 ≤ t ≤ 3, which means you can drive for at most 3 hours.
The constraints for the distance are: 0 ≤ d ≤ 55t, which means the distance you drive cannot exceed 55 miles per hour multiplied by the number of hours you drive.
Part B:
No, it is not possible for you to have driven 160 miles. Let's substitute t = 3 into the distance constraint:
d ≤ 55t
d ≤ 55(3)
d ≤ 165
Since 160 is greater than 165, it is not within the range of possible distances you can drive.
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The system of inequalities describing the possible numbers of hours and distance is t ≤ 3 and d = t × 55. It is not possible to have driven exactly 160 miles.
Part A:
To describe the possible numbers of hours and distance you may have to drive, we can create a system of inequalities based on the given conditions. Let's denote 't' as the number of hours you drive and 'd' as the distance you cover.
The maximum allowed driving time is 3 hours, so we can write the inequality: t ≤ 3.
Since your maximum speed is 55 miles per hour, the distance 'd' can be calculated using the formula: d = t × 55.
Combining these two inequalities, we have: t ≤ 3 and d = t × 55.
Part B:
To determine if it is possible to have driven 160 miles, we substitute the distance 'd' with 160 in the inequality: d = t × 55. By solving for 't', we can find the allowed range of hours. Plugging in the values, we get: 160 = t × 55. Rearranging the equation, we find t = 160 / 55, which gives t ≈ 2.91.
Therefore, it is not possible to have driven exactly 160 miles, as it falls outside the allowed range of t.
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Answer:
583$
Step-by-step explanation:
6% is equal to 0.06, so you multiply 550 by 0.06. which equals 33. Then, because it asks for how much Katie played, including the tax and TV, you add 33 to 550.
Answer:
Step-by-step explanation:
We know that the general equation of a circle can be written as :
(1), where (center )= (h,k) and r= radius
As per given , we have
(h,k) = (5,-4)
(x,y) =(-3,2)
Substitute these value in equation (1), we get
Since radius cannot be negative , thus r= 10 units
Put value of and (h,k) in equation (1), we get
Thus , the equation of given circle is .
A. 75/21
B. 7/9
C. 7/25
D. 21/75
B.The range is all real numbers greater than or equal to 1.
C.The y-intercept is 3.
D.The graph of the function is 1 unit up and 2 units to the left Efrom the graph of y = x2.
F.The graph has two x-intercepts.
This is a polynomial function called Quadratic Function. This is written as:
Recall that the graph of a quadratic function is a special type of U-shaped curve called parabola. The graph of this function is shown in the Figure below. From that, we can say the following:
A. The domain is all real numbers.
This is true. In fact, the domain of any polynomial function is the set of all real numbers.
B. The range is all real numbers greater than or equal to 1.
This is false. Instead, the range is all real numbers greater than or equal to 2, that is the of the vertex.
C. The y-intercept is 3.
This is true. We can find the letting , so:
D. The graph of the function is 1 unit up and 2 units to the left from the graph of
This is false. The correct statement is that the graph of the function is 2 units up and 1 unit to the left from the graph of
E. The graph has two x-intercepts.
This is false. As shown the graph below, this function does not have any
Answer:
A and C
Step-by-step explanation:
Which of the following is the first correct step to write the above equation in the form (x − p)2 = q, where p and q are integers?
Subtract 5 from both sides of the equation
Add 3 to both sides of the equation
Add 5 to both sides of the equation
Subtract 3 from both sides of the equation
The given quadratic equation can be represented in the form
by adding 3 to both sides of the equation.
The polynomial equation whose highest degree is two is called a quadratic equation. The equation is given by
where .
The given quadratic equation is
Case 1: Subtract 5 from both sides of the equation
i.e.
⇒
The LHS of the above equation can not be expressed in form. Hence, it is not the correct step.
Case 2: Add 3 to both sides of the equation.
i.e.
⇒
⇒
⇒
The above equation is expressed in form where p = 4 and q = 3.
Case 3: Add 5 to both sides of the equation
i.e.
⇒
The LHS of the above equation can not be expressed in the . Hence, it is not the correct step.
Case 4: Subtract 3 from both sides of the equation
i.e.
⇒
The LHS of the above equation can not be expressed in the . Hence, it is not the correct step.
Hence, "Add 3 to both sides of the equation" is the correct step.
Learn more about quadratic equations here:
brainly.com/question/2263981?referrer=searchResults
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