Find the y-intercept of y=4(1/3)^x+1+2

Answers

Answer 1
Answer: y intercept is where the line crosses the y axis, that only happens when x=0
so set x=0 and find what y intercet is

y=4(1/3)^0+1+2
y=4(1)+1+2
y=4+1+2
y=5+2
y=7


y intercept is y=7 aka the point (0,7)

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Mario claims that a rhombus is sometimes a square, but a square is always a rhombus. Is he correct? Explain your answer.

Answers

That is correct.This is because a square has all the elements a rhombus has.A rhombus has 4 equal sides,just like a square does.And,a rhombus can't always be a square becase a square also contains 4 equal angles,while a rhombus doesn't.
yes he is a square and a rhombus are exactly the same shape and figure they both have 4 sides and can sometimes have all equal sides :)

Find the area of the figure below. Use 3.14 for pi.



Area = __ feet squared

Answers

Answer:

you then get 130.24 ft squared.

Step-by-step Explanation:

its 80ft for the square + the diameter of the half circle which is 50.24ft, and you then get 130.24 ft squared.

Jane has 4 blue marbles, 3 red marbles, and 2 yellow marbles in a bag. Jane will randomly pick one marble from the bag. What is the probability the marble will be yellow?

Answers

4+3+2= 9, so 2 yellow out of all 9 is 2/9.

What is the area of rectangle ABCD? 43 units2 52 units2 104 units2 208 units2

Answers

The area of rectangle ABCD is 104 square units.

What Is the Area of a Rectangle in Geometry?

The area of the space occupied within the perimeter of a rectangle is called the area of a rectangle. It is calculated by finding the product of the length and breadth of the rectangle.

What Is the Perimeter and Area of a Rectangle?

The perimeter of a rectangle is the sum of its four sides. Hence, Perimeter of Rectangle = 2 (Length + Width) units. The area of a rectangle is defined as a product of length and width. It is expressed in terms of squareunits.

Learn more about Rectangle here brainly.com/question/25292087

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Answer:

The answer is 104 units squared or C on edge

Step-by-step explanation:

Can any one help me if you do you will recive 30 points please help :,(

Answers

1. so since we assume that CF is a straight line that means that the angle CAF is 180 angle CAD is 90 and FAE is 65 so 180-(65+90)=DAE=25

2. so since angle QPR= angle TPS (both are signified by f) and we assume that QT is straight so then QPT=180
180-154=2f=26
angle f=13
QPR=13

3. so we assume that BG is straight so it is 180
we add up the known angles (BQD+DQE+FQG=10+103+12=125) 180-125=DQC+EQF=55=2x+3x=5x
5x=55
x=11
CQD=2x=22
EQF=3x=33

4. we know that x=x and the whole is 360 so
x+x+x+x+71+71+71+71=360=4x+284=360
4x=76
x=19

8. so we assume that EF and CD are straight lines so EQD=CQF so 155=56+3x so
99=3x
CQG=99

9. so adjacent and the ratio is 4:5 so a line is 180 so 4+5=9 180/9=20  20*4=80 20*5=100 4:5 =80:100

a. 80 and 100
b. you should be able to do this

10. so on a line is 180
a. 3:4:5  3+4+5=12  180/12=15
3*15=45  4*15=60  5*15=75
3:4:5 =45:60:75
the angles are 45 60 75

b. you should be able to do this from my work

A 1350 kg car travels at 12 m/s. What is it's kinetic energy

Answers

energy is always transformed from one form to another

energy is not created nor destroyed

so when a car starts moving the chemical potential energy of the car is converted to kinetic energy

kinetic energy is the energy that moving objects possess

kinetic energy formula is as follows

Kinetic energy = 1/2 mv²

where m - mass

v - velocity

substituting these values


K.E = 1/2 x 1350 kg x (12 m/s)²

= 1/2 x 1350 x 144 = 97200 J

the kinetic energy of the car is 97.2 kJ

Hello!

A 1350 kg car travels at 12 m/s. What is it's kinetic energy ?

We have the following data:  

m (mass) = 1350 kg  

v (velocity) = 12 m/s  

KE (kinetic Energy) = ? (in Joule)  

Formula to calculate kinetic energy:

\boxed{KE = (1)/(2) *m*v^2}

Solving:

KE = (1)/(2) *m*v^2

KE = (1)/(2) *1350*12^2

KE = (1)/(2) *1350*144

KE = (194400)/(2)

\boxed{\boxed{KE = 97200\:Joule}}\:or\:\boxed{\boxed{KE = 97.2\:kJ}}\Longleftarrow(kinetic\:energy)\:\:\:\:\:\:\bf\blue{\checkmark}

_______________________

\bf\green{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}