MATHEMATICS HIGH SCHOOL

PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

Answers

Answer 1

Answer:

Answer:

(-6,9,-3)

Step-by-step explanation:

-3x -y +z=6

-3x-y+3z =0

x-3z =3

Multiply the second equation by -1

-1 *(-3x-y+3z) =0*-1

3x +y -3z =0

Add this to the first equation

-3x -y +z=6

3x +y -3z =0

----------------------

0 + 0 + -2z = 6

Divide by -2

-2z/-2 = 6/-2

z = 6/-2

z=-3

Take the third equation to find x

x-3z=3

x-3(-3) = 3

x+9=3

Subtract 9 from each side

x+9-9 =3-9

x=-6

Now we need to find y

3x +y -3z =0

3(-6) +y -3(-3) =0

-18 +y +9=0

-9+y =0

Add 9 to each side

-9+9+y = 0+9

y=9

(-6,9,-3)

Answer 2

Answer:

$\left\{\begin{array}{ccc}-3x-y+z=6\n-3x-y+3z=0\nx-3z=3&|\text{add 3z to both sides}\end{array}\right\n\nx=3+3z\n\n\text{Substitute it to the first and the second equation:}\n\n\left\{\begin{array}{ccc}-3(3+3z)-y+z=6\n-3(3+3z)-y+3z=0\end{array}\right\n\n\text{use distributive property}\n\n\left\{\begin{array}{ccc}-9-9z-y+z=6&|\text{add 9 to both sides}\n-9-9z-y+3z=0&|\text{add 9 to both sides}\end{array}\right\n\n\text{combine like terms}$

$\left\{\begin{array}{ccc}-8z-y=15\n-6z-y=9&|\text{change the signs}\end{array}\right\n\n\underline{+\left\{\begin{array}{ccc}-8z-y=15\n6z+y=-9\end{array}\right}\qquad\text{add both sides of the equations}\n.\qquad-2z=6\qquad\text{divide both sides by (-2)}\n.\qquad\boxed{z=-3}\n\n\text{Put the value of z to the second equation:}\n\n6(-3)+y=-9\n-18+y=-9\qquad\text{add 18 to both sides}\n\boxed{y=9}\n\n\text{Put the value of z to the equation}\ x=3+3z:\n\nx=3+3(-3)\nx=3-9\n\boxed{x=-6}$

$Answer:\ \boxed{x=-6,\ y=9,\ z=-3\to(-6,\ 9,\ -3)}$

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Mrs. aviles is planning a fruit-cup party for a class of 18 students and two teachers. She spends $10 for a package of snacks and also takes orders in advance for fruit cups that cost $3 each. 1. describe the domain of the function both in words and numbers?
2. what is the range?

Answers

Answer:

domain is x = 3

Thus domain means that for every fruit cup costs $3

Range is f(20) = 60

Step-by-step explanation:

We are given;

Total students for the fruit cup party = 18

Total teachers for the fruit cup party = 2

Cost of each fruit cup =$ 3

Delivery charge = $ 10

Now, the total number of people attending the party = Total number of students + Total number of teachers

Thus;

Total number of people attending party = 18 + 2 = 20

Since cost of each fruit cup is $3.

Thus, for 20 fruit cups, the function is;

f(x) = 20x where x is cost of each fruit cup.

It means the cost of 20 fruit cups = $3 × 20 = $60

Thus, domain is x = 3

Thus domain means that for every fruit cup costs $3

Range is f(20) = 60

For a science experiment, Mr. Barrows divides 3/4 cup of salt into small jars, each containing 1/10 cup. If he has 1/7 cup of salt left over, how many jars does he fill? Enter an expression you could use to solve the problem.

Answers

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Initial cup of salt = 3/4 cups ; divided into small jars

Fraction of salt in small jars = 1/10 cup

Fraction left over = 1/7 cup

Number of jars filled?

The fraction divided into the jars :

Initial amount - left over

3/4 - 1/7

(21 - 4) / 28

17 / 28

Fraction of salt per jar = 1/10

Number of jars filled :

Total fraction divided into jars / fraction of salt per jar :

(17 / 28) ÷ (1 /10)

(17 / 28) * (10 / 1)

170 / 28

= 6.0714

= 6 jars

Find the difference. (2x^2 - 3x + 7) - (x^2 + 6x - 12)A) A) x^2 + 3x - 5

B) x^2 - 3x + 19

C) x^2 - 6x + 12

D) x^2 - 9x + 19

Answers

Its D.

(2x^2 - 3x + 7) - (x^2 + 6x - 12)

Distribute the negative over the second parentheses:-

= (2x^2 - 3x + 7) - x^2 - 6x + 12

= x^2 - 9x + 19 (answer)

The factorization of 8x3 – 125 is (2x – 5)(jx2 + kx + 25). What are the values of j and k?

Answers

If you would like to find the values of j and k, you can do this using the following steps:

8x^3 - 125 = (2x - 5) * (jx^2 + kx + 25)
8x^3 - 125 = 2jx^3 + 2kx^2 + 50x - 5jx^2 - 5kx - 125

8x^3 = 2jx^3
4x^3 = jx^3
j = 4

2kx^2 + 50x - 5jx^2 - 5kx = 0
2kx^2 + 50x - 20x^2 - 5kx = 0
2kx^2 - 20x^2 + 50x - 5kx = 0
2kx - 20x + 50 - 5k = 0
2x(k - 10) = 5k - 50
2x(k - 10) = 5(k - 10)
k = 10

The correct result would be: j = 4 and k = 10.

Answer:

j=4 k=10 on edg ;)

Step-by-step explanation:

Find the slope and y intercept
y=2

Answers

y = 0x + 2

Slope = 0

Y-intercept = 2

The line is parallel to the x-axis,
so there is no x-intercept.

Select the property of equality used to arrive aSelect the property of equality used to arrive at the conclusion.If x = 2, then x + 8 = 10

a.the multiplication property of equality

b.the division property of equality

c.the addition property of equality

d.the subtraction property of equality

Answers

would it be b

I really don't know thou

the answer would be D., x+8=10 you are going to subtract 8 from both sides to get x=2

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