Answer:What part of the amino acid contributes to the hydrophobic behavior of a region of the polypeptide?":
The hydrophobic behavior of a region of the polypeptide is primarily influenced by the presence of nonpolar amino acids with bulky side chains, such as alanine, valine, leucine, isoleucine, phenylalanine, and tryptophan. These nonpolar side chains do not interact with water molecules and instead fold away from water to minimize contact with the polar environment.
B) Inoculate infected amphibians with Jl, and determine whether the amphibians recover from infection by chytrids.
C) Take infected amphibians and assign them to two populations. Leave one population alone; inoculate the other with Jl. Measure the rate at which infection proceeds in both populations.
D) Take infected amphibians and assign them to two populations. Inoculate one population with a high dose of Jl; inoculate the other with a low dose of Jl. Measure the survival frequency in both populations.
Answer:
C: Take infected amphibians and assign them to two populations. Leave one population alone; inoculate the other with Jl. Measure the rate at which infection proceeds in both populations.
Explanation:
In scientific investigations, the best way to determine the effect of certain experimental factor on the population of study is to have a baseline for comparison. This is usually referred to as controlled experiment.
In the case of the observation that chytrid infection in amphibians seems to be inhibited by Janthinobacterium lividum, the best way experimental design is to get a population of amphibians suffering from the disease, divide them into two groups and subject them to the same conditions except the introduction of Janthinobacterium lividum to the skin of one of the groups.
A suitable method can thereafter be employed to measure the rate at which infection proceeds in both population. If indeed, the bacterium has the capacity to inhibit the infection, the rate of infection in the group with the bacterium will be significantly less than that of the group without the bacterium.
The correct option is C.
Word Bank:
Initial observation, hypothesis, experiment, observation and analysis of data, Interpretation, final hypothesis supported.
1. The researchers sampled all the plots throughout the growing season. They measured growth rates, and they analyzed the chemical composition of living leaves.
2.The researchers inferred that something limits grass growth in some places. It could be any environmental factor- temperature, sunlight, water or nutrients. Based on their knowledge of salt marshes, they proposed an idea: Marsh grass growth is limited by available nitrogen.
3. Data analysis confirmed that marsh grasses in experimental plots with additional nitrogen grew taller and larger than the controls.
4. Researchers observed that marsh grass grows taller in some places than in others. This observation led to a question: Why do marsh grasses grow to different heights in different places?
5. The researchers selected similar plots of marsh grass. All plots had similar plant density, soil type, input of fresh water, and height above average tide level. The plots were divided into control and experimental groups.
6. The researchers complied all of the data. They compared the average growth rate in each plot and the average height of the plants.
1. Observation and Analysis of Data
2. Hypothesis
3. Final Hypothesis Supported
4. Initial Observation
5. Experiment
6. Interpretation
The box of information can be classified according to stages of scientific methodology as Observation and Analysis of Data, Hypothesis, Interpretation, Initial Observation, Experiment, and Final Hypothesis Support.
Here's how each part of the experiment corresponds to stages of the scientific methodology:
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Answer:
Genotype of offspring: bb
Phenotype of offspring: white
Percentage of white offspring: 100%
Percentage of black offspring: 0%
Explanation:
Black with allele B is dominant to white with allele b.
Homozygous white will have the genotype bb.
Crossing two homozygous white cats:
bb x bb = bb, bb, bb, and bb
All the offspring will be homozygous white with bb genotype.
Percentage of the offspring that are white = 100%
Percentage of the offspring that are black = 0%
Answer:
The offspring will also be white and homozygous.
Explanation:
If the two cats are white and homozygous where the gene B is for black color and dominant, gene b is for white color and recessive. In this case the genotypes of the two cats are going to be "bb" which can only lead to the same genotypes and phenotypes in their offspring. They will also be white and homozygous.
I hope this answer helps.
B) Calculate the probability of children with both cystic fibrosis and polydactyly when parents are each heterozygous for both genes.
C) Calculate the probability of each of four children having cystic fibrosis if the parents are both heterozygous.
D) Calculate the probability of a child having either sickle-cell anemia or cystic fibrosis if parents are each heterozygous for both.
E) Calculate the probability of purple flower color in a plot of 50 plants seeded from a self-fertilizing heterozygous parent plant.
Answer:
True
Explanation:
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