Answer:
(B) L=W; F=D
Explanation:
Since the airplane's velocity is constant, the airplane is not accelerating in any direction. In absence of acceleration, all forces acting on the plane are balanced so that the net forces in the horizontal and the vertical directions are zero. Given the drawing, this implies that
Forward force = Drag force (F=D)
Weight = Lift (W=L)
which corresponds to option (B)
(it is not C because nothing in the text says that the vertical and horizontal components have to have same magnitude)
The relationship between the magnitudes of the forces is that lift force is equal to weight force, and drag force is equal to thrust force.
In this scenario, the airplane is flying at a constant velocity, which means that its acceleration is zero. According to Newton's first law of motion, if an object is moving with a constant velocity, the net force acting on it is zero.
Therefore, the relationship between the magnitudes of the four forces shown in the diagram is that the lift force (L) is equal to the weight force (W), and the drag force (D) is equal to the thrust force (F).
So, the correct answer is C. L = W = F = D.
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slugs are the only member of what that have no shells
Answer: 3m/s^2
Explanation:
Given that:
Acceleration of object = ?
Force = 9 N
Mass of object = 3 kg
Since force is the product of the mass of an object and the acceleration by which it moves i.e Force = mass x acceleration
9N = 3kg x acceleration
Acceleration = 9N/3kg
Acceleration = 3m/s^2 (3 metres per second square)
Thus, an acceleration of 3m/s^2 is produced.
B. 3 kg-m/s
C. 15 kg-m/s
D. 10 kg-m/s
The momentum of a book with a mass of 5 kg is pushed off a table with a velocity of 2 m/s is option D. 10 kg-m/s.
Here,
p = momentum
m = mass
v = velocity
p = mv
=5×2
=10 Kg*m/s
Hence, the momentum of a book with a mass of 5 kg is pushed off a table with a velocity of 2 m/s is option D. 10 kg-m/s.
To learn more about momentum, refer to: brainly.com/question/26138070
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Momentum=Mass•Velocity
=5 kg•2 m/s
=10 kg-m/s
In layman's term: like charges don't attract while opposite charges doelectrostatic forces between point A( which is charged) and point B (which is also charged) are proportional to the charge of point A and point B. there is also something else about this law that I don't quite remember.
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Here is the formula:
F = k x Q1 x Q2/d^2
What the formula means:
F=force between charges
Q1 and Q2= amount of charge
d=distance between these two charges
k= Coulombs constant (proportionally constant)
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I think that about covers it and hopefully this helped.