Answer:
I would just say that Manuel seems to be moving at a pretty fast or decent pace at first, and he then at some point, doesn't move at all because the straight line shown in the middle of the graph shows us that there isn't any movement from him. (at least with what the information on the graph is giving us) At the very end of the graph, I can see that he eventually reached his destination, and at a very fast rate! (because the graph seems to obviously end at a point)
Step-by-step explanation:
I'm a Freshman in High School, and I haven't learned about graphs as simple as this one in a hot-minute! [a year or two maybe] Sooo...I hope I helped a little bit though.
But even if I am completely wrong, just know that whenever a straight vertical line like that is on a graph, it means that there was either NO motion detected or that there wasn't any data at that moment to be graphed. {BUT} In this case, Manual wasn't moving at all for that time being, because the graph has a STRAIGHT VERTICAL LINE in the middle of it.
I would also write down in my answer, that it looks like he was riding a bike, or was driving, or was maybe running, because it looks like either his destination was very close to where he originally started, OR he just got to his destination quickly via transportation.
Answer:
y=3x+21
Step-by-step explanation:
The slope is 3. so let's write a slope intercept form.
y=3x+b
let's plug in the y and x values
3=3(-6)+b
3=-18+b
add 18 to both sides
21=b
b=21
B) $22,000
C) $21,000
D) $20,000
Answer: C) $21,000
Step-by-step explanation:
Given : Pat bought a boat for $37,000 in 2001. In 2006 the boat was worth $27,000.
If the boat depreciation is linear, then the amount by which the value of boat depreciates must be constant.
Let x be the constant depreciation in the value of boat per year.
Then , the value of boat (in dollars) after n years from 2001 is given by :-
(1)
For year 2006 , n=5 and V = 27000
Then ,
i.e.
i.e.
i.e.
Thus , the constant amount of depreciation in the value of boat per year. = $2000
Now for year 2009 , put in n=8 and x= 2000 in (1), we get
Hence, the value of boat in 2009 = $21,000
Answer:
4x^2 + 3x - 9
Step-by-step explanation:
First, add together functions R(x) and S(x). Stack them vertically and combine like terms:
R(x) = 2 - x^2
S(x) = 2x + 5
------------------
(R+S)(x) = -x^2 + 2x + 7
Now subtract the above result from Q(x):
Q(x) - (R(x) + S(x)) = 3x^2 + 5x - 2 + x^2 - 2x - 7, or 4x^2 + 3x - 9
(6y + 8)(y - 6)
6(y + 8)(y - 1)
6(y - 1)(y - 7)
Answer:
6 (y + 8) (y - 1)
Step-by-step explanation:
Factor the following:
6 y^2 + 42 y - 48
Factor 6 out of 6 y^2 + 42 y - 48:
6 (y^2 + 7 y - 8)
The factors of -8 that sum to 7 are 8 and -1. So, y^2 + 7 y - 8 = (y + 8) (y - 1):
Answer: 6 (y + 8) (y - 1)
PS: it's really helpful to pose the question correctly 6 y^2 + 42 y - 48 NOT
6y 2 - 48 + 42y
Answer:
6 (y + 8) (y - 1)
Step-by-step explanation: