Molar Mass of N2 = 28.02 g/mol
Molar Mass of H2 = 2.02 g/mol
Molar Mass of NH3 = 17.04 g/mol
Answer:
N₂
Explanation:
The limiting reactant is the one that gives the smaller amount of product.
Assemble all the data in one place, with molar masses above the formulas and masses below them.
M_r: 28.02 2.02 17.04
N₂ + 3H₂ ⟶ 2NH₃
m/g: 5.42 5.42
1. Calculate the moles of each reactant
2. Identify the limiting reactant
Calculate the moles of NH₃ we can obtain from each reactant.
From N₂:
The molar ratio of NH₃:N₂ is 2:1.
From H₂:
The molar ratio of NH₃:H₂ is 3:2.
N₂ is the limiting reactant, because it gives the smaller amount of NH₃.
B. potassium
C. hydrogen
D. lithium
Answer: C. hydrogen
Explanation:
Atomic radius of an atom is defined as the total distance from the nucleus to the outermost orbital of electron.
On moving from top to bottom, there is an addition of shell around the nucleus and the outermost orbital gets far away from the nucleus and hence, the distance between the nucleus and outermost orbital increases.
This in turn increases the atomic radii of the element from moving top to bottom in a group.
a) How many grams of iron can be made from 6 moles H2
223.4 g of iron can be formed from 6 moles of hydrogen gas.
Explanation:
Fe₂O₃(s) + 3 H₂(g) → 2 Fe(s) + 3 H₂O(l)
Since the given equation is the balanced one, we need 3 moles of hydrogen gas to make 2 moles of iron, so the molar ratio is 3:2. So, from 6 moles of hydrogen gas, we can make few moles of iron as,
Molar mass of iron = 55.85 g
So amount of iron produced = 4 moles × 55.85 g/mol = 223.4 g of iron