Gerry has two different part-time jobs, and he had work 20 hours per week at each job. He earns $8 per hour at one job. Which expression represents how much Gerry earned last week if he earns d dollars per hour at this other job?A- 20+20d
B- 160+ 20d
C- 40+ d
D- 160+ 8d
                                PLZZZZZZ ANSWER THX!!!!!!

Answers

Answer 1
Answer: The correct answer for the question that is being presented above is this one: "Last week's earnings = 40d."

Gerry has two different part-time jobs, and he had work 20 hours per week at each job. He earns $8 per hour at one job. 

Last week's earnings = 20d + 20d
Last week's earnings = 40d.
Answer 2
Answer:

20d+20Answer:

Step-by-step explanation:


Related Questions

Write 5.0062x10 squared 3 in standard form
What is the three equivalent ratio of 5/7
Please help ASAP. PRE ALGEBRA
Today, the Great Pyramid at Giza near Cairo, Egypt stands 137 meters tall, coming to a point.Its base is a square with each side measuring 230 meters wide. What is the slope of the pyramid?
How do you factorise 8p-12

assume that the unit cost of making a product is $1.32. For every unit sold, the firm wants 20% to represent profit. Applying the standard markup approach, what should the selling price be?

Answers

Answer:

$1.26

Step-by-step explanation:

all you have to do is add 32+20=26 then bring down 1

What is twenty five times three?

Answers

To find 25x3, you could just add 25 3 times like this 25+25+25.  But since 4 quarters equaling 25 cents each is 100 cents, 3 quarters is 75 cents.  That being said, 25x3=75
twenty five times three is 75

2. If y varies inversely as x and
y = 3 when x = 5, find x when y = 2.5

Answers

Answer:

Step-by-step explanation:

From the law of variation,

y <> 1/x, where <> is the constant of proportionality. Therefore

y = k/x where k is a constant

3 = k/5 and k = 15

To find x when y = 2.5(5/2)

Go back to the second equation

y = k/x

5/2 = 15/x

When you cross multiply

5x = 30.

Divide through by 5,

x = 6.

Amie published her first book. She was given $20,000 and an additional $0.15 for each copy that sold. Her earnings,d, in dollars,from the publication of the book are given d=20,009 + 0.15n where n is the number of copies sold. During the first year, Amie earned $22,100 from the publication and the sale of her book. How many copies of her book were sold?

Answers

Answer: 139 copies of her book were sold.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

Earnings (d)  

  • d= 20,009+0.15n

Where "n" is the number of copies sold.

If she earned $22,100, we have to replace the value of d by the number given:

22,100 = 20,009 +0.15 n

Solving for n

22,100-20,009 = 0.15n

2,091=0.15n

2,091/15=n

139.4=n

n≅139 books (rounded)

Feel free to ask for more if needed or if you did not understand something.  

d=20,009 + 0.15n
$22,100 = 20,009 + 0.15n
$2091 = 0.15n
n = 2091/.15 = 13940

In scalene triangle abc angle b is 45 degrees, and angle c is 55 degrees.What is the order of the sides in length from longest to shortest

Answers

First, let's find angle A.

The angles of a triangle always add up to 180 degrees.
A + B + C = 180
A + 45 + 55 = 180
A + 100 = 180
A = 80 degrees

The longest side is always opposite the largest angle.
Since A is the largest angle, the longest side is BC.
The next largest angle is C, and the next longest side is AB.
And the smallest angle B gives us the shortest side AC.

Therefore, your answer would be BC, AB, AC.

Let f(x)=2/x-3. Find f^-1(x)

Answers

Answer:

Two questions:

Question 1: f^(-1)(x)=? given f(x)=(2)/(x)-3.

Answer 1: f^(-1)(x)=(2)/(x+3)

Question 2: f^(-1)(x)=? given f(x)=(2)/(x-3).

Answer 2: f^(-1)(x)=(2)/(x)+3

Step-by-step explanation:

So f^(-1) is used in most classes to represent the inverse function of f.

The inverse when graphed is a reflection through the y=x line. The ordered pairs (a,b) on f implies (b,a) are on f^(-1).

This means we really just need to swap x and y.

Since we want to write as a function of x we will need to solve for y again.

Question 1:

y=(2)/(x)-3

Swap x and y:

x=(2)/(y)-3

We want to solve for y.

Add 3 on both sides:

x+3=(2)/(y)

Make the left hand side a fraction so we can cross-multiply:

(x+3)/(1)=(2)/(y)

Cross multiply:

y(x+3)=1(2)

Simplify right hand side:

y(x+3)=2

Divide both sides by (x+3):

y=(2)/(x+3)

So f^(-1)(x)=(2)/(x+3).

Question 2:

y=(2)/(x-3)

Swap x and y:

x=(2)/(y-3)

Make left hand side a fraction so we can cross multiply:

(x)/(1)=(2)/(y-3)

Cross multiply:

(y-3)x=1(2)

We have to distribute here:

yx-3x=2

Add 3x on both sides:

yx=2+3x

Divide boht sides by x:

y=(2+3x)/(x)

You could probably stop here but you could also simplify a little.

Separate the fraction into two terms since you have 2 terms on top bottom being dividing by x:

y=(2)/(x)+(3x)/(x)

Simplify second fraction x/x=1:

y=(2)/(x)+3

So f^(-1)(x)=(2)/(x)+3.