Answer:
catalytic combustor
Explanation:
B. Decrease in bone mass
C. Decrease in fat stores
D. Decrease in muscle mass
Answer:
=
Explanation:
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The state you are referring to is called dynamic equilibrium. In the context of a cell, this means that the concentration of molecules or ions is the same inside and outside the cell,
but particles continue to move across the membrane in both directions at equal rates.
This state is reached when the membrane is selectively permeable and allows for the free diffusion of the particles across the membrane until an equal concentration is reached on both sides.
At dynamic equilibrium, there is no net movement of particles across the membrane, although individual particles continue to move back and forth in both directions.
This is an important concept in cellular physiology, as it allows for the maintenance of homeostasis and proper functioning of the cell.
To know more about dynamic equilibrium refer here
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B. the wavelength
C. the center point
D. the trough point
Answer:
Option (D)
Explanation:
The transverse wave travels in the form of crests and troughs.
The highest point on the wave is called crest.
The lowest point on the wave is called trough.
The part of the wave that best describes lowest point of a wave is the trough (option D)
To know the correct answer to the question, we shall define each option. This is shown below:
Crest of a wave is simply defined as the highest point or peak of a wave. It is the point on the wave propagation where the displacement is at its highest positive value.
Wavelength of a wave is the distance between two successive crest or trough of a wave propagation.
Center point of a wave is simply refer to the rest or equilibrium point of the wave
Trough of a wave is simply the defined as the lowest point of the wave, where the displacement of the wave is maximum in negative values.
With the above information in mind, we can conclude that the correct answer to the question is trough point (option D)
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Answer:
L' = 555.95 lb
Explanation:
Analyzing the given conditions in the question, we get
The safe load, L is directly proportional to width (w) and square of depth (d²)
also,
L is inversely proportional length (l) i.e L = k/l
combining the above conditions, we get an equation as:
L = k(wd²/l)
now, for the first case we have been given
w = 3 in
d = 6 in
l = 11 ft
L = 1213 lbs
thus,
1213 lb = k ((3 × 6²)/11)
or
k = 123.54 lbs/(ft.in³)
Now,
Using the calculated value of k to calculate the value of L in the second case
in the second case, we have
w = 6 in
d =3 in
l = 12 ft
Final Safe load L' = 123.54 × (6 × 3²/12)
or
L' = 555.95 lb
The load that a beam of the given dimensions can support is derived using a joint variation formula. The constant of variaiton is found using the given beam's characteristics, and then applied on the second beam's measurements to find its load. The result is approximately 2025 pounds.
The question is related to joint variation and its principles in mathematics. First, it's necessary to define the equation of the joint variation:
L = k*(w*d^2)/l
where L is the load, w is the width, d is the depth, l is the length, and k is the constant of proportionality. From the information given in the question, we can derive that k equals to 1213 * 11 / (3 * 6^2), which is approximately 135. Then, we substitue the values of the second beam into the equation, w = 6, d = 3, l = 12 and k = 135, to get the load L for the second beam, which equates to about 2025 pounds.
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