b. Neither effectively nor efficiently
c. Efficiently, but not effectively
d. Both effectively and efficiently
The product of two consecutive positive integers is 27 more than 5 times the larger
Answer:
in the explanation
Step-by-step explanation:
In the number line, the left most number would be -200 as it's the lowest, the middle would be -150, as this number is in between the other two, and the right most would be 75, as it's the greatest.
Hope this helps!
Answer:
awnser one is 7 and question 2 is -10
Step-by-step explanation:
−12−2−−55=? question one
In the first fraction, the negative numerator and negative denominator cancel each other.
Since the the second fraction is negative and you are subtracting, remove the negative sign and switch the operation to addition.
The equivalent equation is
122+55=?
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(12/2, 5/5) = 10
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
(122×55)+(55×22)=?
Complete the multiplication and the equation becomes
6010+1010=?
The two fractions now have like denominators so you can subtract the numerators.
Then:
60+1010=7010
Since 70 divided by 10 equals 7 then,
7010=7
Therefore:
−12−2−−55=7
Question 2
−81+6−3=?
In the second fraction, move the negative sign from the denominator to the numerator and the value remains the same.
The equivalent equation is
−81+−63=?
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(-8/1, -6/3) = 3
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
(−81×33)+(−63×11)=?
Complete the multiplication and the equation becomes
−243+−63=?
The two fractions now have like denominators so you can add the numerators.
Then:
−24+−63=−303
Since -30 divided by 3 equals -10 then,
−303=−10
Therefore:
−81+6−3=−10
Solution by Formulas
Apply the fractions formula for addition, to
−81+6−3
and solve
(−8×−3)+(6×1)1×−3
=24+6−3
=30−3
=−10