The coordinates of the other two vertices are:
(1/2 + √98, 3/2)
(1/2, 3/2 - √98)
If A(-3, -2) and C(4, 5) are the endpoints of a diagonal of a square, and since a square has equal sides and right angles, you can find the other two vertices by considering the properties of a square.
Let's calculate the midpoint of AC, which will be the center of the square. The midpoint of AC can be found by averaging the coordinates of A and C:
Midpoint M = ((-3 + 4) / 2, (-2 + 5) / 2) = (1/2, 3/2)
Now, we know the center of the square is at (1/2, 3/2).
To find the other two vertices, we'll move from the center in different directions.
Since a square has four equal sides, the distance from the center to any corner will be the same as the distance from A to C.
The distance between A and C can be found using the distance formula:
So, the distance from the center to any corner is √98.
Now, we can find the other two vertices by moving √98 units from the center in different directions.
One vertex is √98 units to the right of the center: (1/2 + √98, 3/2)
One vertex is √98 units below the center: (1/2, 3/2 - √98)
For similar question on vertices.
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Answer:
B(4,-2) D(-3,5)
Step-by-step explanation:
you must graph the points and project the lines in X and Y until they intersect and form a square
I attached an image
Answer:
Step-by-step explanation:
10 divided by 12= 0.83
0.83 times 5= 4.16 or 26/625
__ cm3
Express the answer in simplest form.