How many moles of tungsten atoms are in 4.8 × 1023 atoms of tungsten?

Answers

Answer 1
Answer:

Answer:-  0.80 moles

Solution:- Number of atoms of tungsten are given and we are asked to calculate the moles of tungsten atoms. So, it is a atom to mole conversion and for this we use the Avogadro number.

Number of atoms are divided by Avogadro number to get the number of moles.

Avogadro number is 6.022*10^2^3 . Given number of atoms is 4.8*10^2^3 . let's divide it by Avogadro number.

4.8*10^2^3atoms((1mol)/(6.022*10^2^3atoms))

Numerator and denominator has equal exponent so it is canceled. So, we only need to divide 4.8 by 6.022 and round the answer to two sig figs as given number of atoms has only two sig figs.

4.8((1mol)/(6.022))

= 0.80 moles

Hence, there are 0.80 moles of tungsten atoms in given number of atoms.


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20 g of sugar is stirred into a beaker containing 100 g of water. After the sugar has completely dissolved, the solution is put on a scale. What is the mass of the solution?

Answers

The mass of the solution of sugar and water is 120 grams.

What is mass?

Mass is the quantity of matter of a physical body.

The mass of the sugar is given is 20g

The mass of the water is 100 g.

100 + 20 = 120 gram

Thus, the mass of the solution of sugar and water is 120 grams.

Learn more about mass

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The mass of the solution should be 120g since 20g of sugar were added to 100g and 100+20=120.
I hope this helps.  Let me know in the comments if anything is unclear.  

What is 850 torr= ? Atm

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850 torr. times 1 atm./760 torr. or 850/760. So, 1.11842105 atm.

What parts of the cell are used to connect an electrochemical cell to a circuit?

Answers

I think it's the Terminals

Help ! how do I do this

Answers

I think it is going to be 3

If it takes 54ml of 0.1 m naoh to neutralize 125 ml of a hcl solution with unknown concentration, what is the concentration of the hcl?

Answers

the balanced equation for the reaction between NaOH and HCl is as follows
NaOH + HCl ---> NaCl + H₂O
stoichiometry of NaOH to HCl is 1:1
number of NaOH moles reacted - 0.1 mol/L x 0.054 L = 0.0054 mol
number of HCl moles reacted = number of NaOH moles reacted 
since the molar ratio of acid to base is 1:1
therefore number of HCl moles reacted - 0.0054 mol
the number of moles of HCl in 125 mL - 0.0054 mol
therefore number of HCl moles in 1000 mL - 0.0054 mol / 125 mL x 1000 mL 
number of moles of solute in 1000 mL is known as the molarity concentration 
concentration of HCl is 0.0432 M

What sequence of enzymes allows for the synthesis of glycogen from glucose-6-phosphate?a. UDP-glucose pyrophosphorylase, phosphoglucomutase, glycogen synthase, amylo-(1,4α1,6)-transglycosylase

b. phosphoglucomutase, UDP-glucose pyrophosphorylase, amylo-(1,4α1,6)-transglycosylase, glycogen phosphorylase

c. phosphoglucomutase, amylo-(1,4α1,6)-transglycosylase, UDP-glucose pyrophosphorylase, glycogen synthase

d. UDP-glucose pyrophosphorylase, phosphoglucomutase, amylo-(1,4α1,6)-transglycosylase, glycogen synthase

e. phosphoglucomutase, UDP-glucose pyrophosphorylase, glycogen synthase, amylo-(1,4α1,6)-transglycosylase

Answers

Answer:

The answer is (e) : phosphoglucomutase, UDP-glucose pyrophosphorylase, glycogen synthase then amylo-(1,4-1,6)-transglycosylase.

Explanation:

Phosphoglucomutase: Convert glucose-6-phosphate to glucose-1-phosphate.

UDP-glucose pyrophosphorylase:  Form UDP-glucose from glucose-1-phosphate.

Glycogen synthase: Add the new glucose from UDP-glucose to the growing glycogen chain.

Amylo-(1,4-1,6)-transglycosylase: This is a branching enzyme, it initiates formation of branches evolving from the main chain.