MATHEMATICS MIDDLE SCHOOL

Pierre wants to make tables and chairs. He has a total of 220 wooden boards and 760 nails. 13T+8C≤220 represents the number of tables T and chairs C he can make with 220 wooden boards. 48T+37 C≤760 represents the number of tables and chairs he can make with 760 nails. Does Pierre have enough boards and nails to make 9 tables and 5 chairs?

Answers

Answer 1

Answer:

Answer:

Pierre has enough boards and nails to make 9 tables and 5 chairs.

Step-by-step explanation:

13T+8C ≤ 220

Let us substitute 9 for T and 5 for C and check.

13(9) + 8(5) = 117 + 40

= 157 < 220

So, 220 wooden boards are sufficient to make 9 tables and 5 chairs.

48T+37C ≤ 760

Substitute 9 for T and 5 for C.

48(9)+37(5) = 432 + 185

= 617 < 760

So, 760 nails are sufficient to make 9 tables and 5 chairs.

Hence, Pierre has enough boards and nails to make 9 tables and 5 chairs.

Answer 2

Answer:

Answer:

Step-by-step explanation:

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Help please K? cya gtg

Answers

Answer:

Pretty sure its Quadratic

Step-by-step explanation:

Linear, needs to be in a straight line.

Quadratic, involving the second and no higher power of an unknown quantity or variable.

Exponential, (of an increase) becoming more and more rapid.

Please help and thank you

Answers

Answer:

Your answer is D. Hoped i helped

Step-by-step explanation:

plot each coordinate, Then see which has the most/all in the shaded area.

What is the sum of the first 4 terms of the arithmeticsequence in which the 6th term is 8 and the 10th term
is 13 ?
F. 10.5
G. 14.5
H. 18
J. 21.25
K. 39.5

Answers

$a_6=8;\ a_(10)=13\n\na_(10)-a_6=4r\n\n4r=13-8\n4r=5\ \ \ \ /:4\nr=1.25\n\na_1=a_6-5r\na_1=8-5\cdot1.25=8-6.25=1.75\n\nS_4=(2a_1+(4-1)r)/(2)\cdot4=(2a_1+3r)\cdot2=4a_1+6r\n\nS_4=4\cdot1.75+6\cdot1.25=7+7.5=14.5$

Final answer:

The sum of the first 4 terms of the arithmetic sequence where the 6th term is 8 and the 10th term is 13 is 14.5.

Explanation:

In an arithmetic sequence, the difference between consecutive terms is constant. This difference is commonly called the common difference. Given that the 6th term is 8 and the 10th term is 13, we can calculate this common difference.

The common difference is (13 - 8) / (10 - 6) = 5 / 4 = 1.25.

The common difference is backward from the 6th term to the first term or we can say the 6th term minus 5 times the common difference will give us the first term. Therefore, the first term is 8 - 5*1.25 = 8 - 6.25 = 1.75.

The sum of the first 4 terms of an arithmetic sequence is given by the formula S = n/2 *[2a + (n-1)*d], where 'n' is the number of terms (in this case 4), 'a' is the first term, and 'd' is the common difference.

Therefore, substituting our known values into the formula gives us: S = 4/2 *[2*1.75 + (4-1)*1.25] = 2*[3.5 + 3.75] = 2*7.25 = 14.5

Learn more about Arithmetic Sequence here:

brainly.com/question/32830972

M stands for a whole number greater than 10 and less than 20n stands for a whole number greater than 2 and less than 10

1. What is the smallest number that m x n could be?
2. What is the largest number that m - n could be?

Answers

10 < m < 20
So m can be 11, 12, 13, 14, 15,16, 17, 18 or 19

2 < n < 10
So n can be 3, 4, 5, 6, 7, 8 or 9
Q1. What is the smallest number that m times n could be? That would be the product (the "times") of the two smallest number in each range, so 11 times 3 = 33.

Q2. What is the largest number that m - n could be? Here we want to make the difference between the two numbers the largest. So we take the largest value for m which is 19 and the smallest number for n, which is 3.

19 - 3 = 16.

Mr.king picked up tomatoes from his garden and got 21 cups of chopped tomatoes. he used 5 1/2 cups of the tomatoes to make spagatti. he also used 2 1/4 cups of the tomatoes to make chilii. he seprated the remaining chopped tomatoes into 2 equals portions and froze them. how many cups of tomatoes were in each portion that he froze?ANSEWERS AVALIABLE
A, 3 7/8 C, 13 1/4
B, 5 5/8 D, 6 5/8

Answers

Start with 21 cups , substract 5.5 (5 and one half) , 2.25( 2 and one fourth), and then divide by two (divided into 2 equal portions) and the result is 6.625 and if you divide the options as an improper fraction, you'll get 6 and five eights... so your answer is D.

2(3x - 1) + 2(4x + 5) = 8