A population of birds has two feather colours, white and black. Black is dominant over white. If you know that 75% of a population of birds totalling 4520 individuals has the dominant phenotype, determine how many individuals are heterozygous? Please show me the mathematical work to get to the answer!! :)

Answers

Answer 1

Answer: Heterozygous means that the bird(s) have the recessive and dominant genotypes. If you have 75% of a population of 4520 birds that have black feathers, that leaves 25% of the population to have white feathers. In order for 25% of the birds to have white feathers, the two genotypes must be Xx and Xx. This leaves the options for the following genotypes when using a punnet square (will add one at the bottom): XX, Xx, Xx, xx. This gives you the percentage of heterozygous birds, which is 50%. If you take 50% of 4520, (4520 x 1/2 = 2,260) that is the number of heterozygous birds in the population.
Final Answer: 2,260 birds are heterozygous.
Punnet Square:
X x
X XX Xx
x Xx xx

Answer 2

Answer:

Final answer:

To determine the number of heterozygous individuals in a population of birds with black and white feather colors, we can use principles of Mendelian genetics and the Hardy-Weinberg equation. By calculating the frequency of the recessive allele and applying the equation 2pq, we can find the number of heterozygous individuals. In this case, the population contains 2260 heterozygous individuals.

Explanation:

To determine the number of individuals that are heterozygous, we need to use the principles of Mendelian genetics. Since black is dominant over white, we can infer that the individuals with the dominant phenotype are homozygous dominant (BB) or heterozygous (Bb).

Let's assume that the population consists of Bb individuals. Given that 75% of the population has the dominant phenotype, the remaining 25% must have the recessive phenotype (bb).

So, the frequency of the recessive allele (b) can be calculated using the Hardy-Weinberg equation: q = √(0.25) = 0.5.

Now, to find the number of heterozygous individuals, we can use the equation 2pq, where p is the frequency of the dominant allele (B) and q is the frequency of the recessive allele (b). Since p + q = 1, we can calculate p using the equation p = 1 - q = 1 - 0.5 = 0.5. Then, we can substitute the values into the equation 2pq:

2 × 0.5 × 0.5 = 0.5

Therefore, there are 0.5 × 4520 = 2260 heterozygous individuals in the population.

Learn more about Heterozygous individuals in a population of birds here:

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Answers

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Answers

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Answers

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Answers

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