Express the fractions one half 3/16 and 7/8 with the lowest common denominator

Answers

Answer 1
Answer: one half would be 8/16, 7/8 would be 14/16, and 3/16 would stay as 3/16. 16 is the common denominator between all of the fractions.

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How many bricks 3.75 in. Wide × 8 in. Long are required to cover a patio 13 ft. 6 in. Wide by 18 ft 9 in. Long ?Step 1. First, find the total width & length of the patio in inches. Step 1a. Convert the portion of width and length that is expressed in feet to inches. Width: 13 ft = 13 × ___ = ___in Length: 18 ft = 18 × ____ = _____ in
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Two blocks are connected by a very light string passing over a massless and frictionless pulley. The 20.0 N block moves 75.0cm to the right and the 12.0 N block moves 75.0cm downward.Find the total work done on 20.0N block if there is no friction between the table and the 20.0N block.

Answers

The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus, 
1.22 a = 12.0 - T  (eqn 1)
and for the 20.0 N block: 
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction) 
2.04 a = T - 6.5  (eqn 2) 

[eqn 1] + [eqn 2] → 3.26 a = 5.5 
a = 1.69 m/s² 


Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5 
T = 9.95 N 

Now want the resultant force acting on the 20.0 N block: 
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N 
Units have to be consistent ... so have to convert 75.0 cm to m: 

75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m 
work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J

Final answer:

The total work done on the 20.0 N block as it moves 75.0 cm to the right, with no friction between the table and the block, is 15 Joules.

Explanation:

In physics, work done by a force is given by the formula Work = Force x Distance x Cos θ, where θ is the angle between the force and the direction of motion. Here, the force is the same as the weight of the 20.0 N block (because weight = mass * gravity, and the mass is the weight divided by gravity, so mass * gravity = weight), and because the block moves horizontally (rightward), θ is 0 degrees. The Cos of 0 degrees is 1.

So, the work done on the 20.0 N block as it moves 75.0 cm (or 0.75 meters, because 1 m = 100 cm) to the right is 20.0 N * 0.75 m * 1 = 15 Joules.

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What is the answer for 3{5[10+5(500-100)+399]}

Answers

Okay. Handle 500-100 first. That brings it to 3{5[10+5(400)+399]}. Next, Handle 5(400). That brings you to 3{5{10+2,000+399]}. Then handle all the addition. That leads to 3[5(2,409)]. Next, configure 5(2409). That leads to 3(12045). Then do that one which ends as 36,135 for a final answer.
Handle 500-100 first. That brings it to 3{5[10+5(400)+399]}. then Handle 5(400). That brings you to 3{5{10+2,000+399]}. next handle all the addition. That brings you to 3[5(2,409)]. Next, configure 5(2409). That gives you 3(12045). Then do that one which ends as 36,135 for a final answer.qx

Sketch one cycle of the sine curve. y = -3 sin 4theta

Answers

Answer:

Step-by-step explanation:

We have been given a function:

y=-3sin4\theta

We will compare it with the genral equation which is:

y=asin bx+c

Where, a is amplitude and period of function is (2\pi)/(b)

In given equation a is -3 and b is 4

So, period of the given equation is:

(2\pi)/(4)=(\pi)/(2)

Yo can look at the graph in the attachment.

The a is the amplitude and the period of the function is (2\pi )/(b)

We have been given a function

y = -3 sin 4 \theta

What is the general form of sin wave?

y=asinbx+c

We will compare it with the general equation which is

Where a is amplitude and period of the function is (2\pi )/(b)

In the given equation a is -3 and b is 4

So, the period of the given equation is:

(2\pi )/(4) =(\pi )/(2)

You can look at the graph.

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A manufacturing firm wants to package its product in a cylindrical container 2ft. high with surface area 6ft^2.
What should the radius of the circular top and bottom​ be?

Answers

To solve the problem above, we will be using the equation in solving the surface area of a cylinder which goes. A = 2pi r^2 + 2pi r h, A is for the surface area, pi is 3.1416; h is the height and r is the radius. Basing on this formula the radius will be 0.3982 ft both top and bottom.

The teacher separated her class of twenty -eight students into two groups. One group has 4 more than twice as many students as the other group. how many students are in each group?

Answers

The class has 28 student. One group has four more students so surat 4 from 28. 28-4=24 since one of the groups have twice as many students as the other divide 24 by 3. 24 / 3 = 8. It says 1 group has for more than twice the other group so that would mean 2/3 of 24 and 4 would be the answer 16+4=20. The first group had 8 students, the other group has 20 students.

What is the solution of x - 13 =5

Answers

If you're looking for x then it would be x=18 since you add 13 to both sides to have x alone
x-13=5
+13=+13
x =18
the answer is x=8