The total work done on the 20.0 N block as it moves 75.0 cm to the right, with no friction between the table and the block, is 15 Joules.
In physics, work done by a force is given by the formula Work = Force x Distance x Cos θ, where θ is the angle between the force and the direction of motion. Here, the force is the same as the weight of the 20.0 N block (because weight = mass * gravity, and the mass is the weight divided by gravity, so mass * gravity = weight), and because the block moves horizontally (rightward), θ is 0 degrees. The Cos of 0 degrees is 1.
So, the work done on the 20.0 N block as it moves 75.0 cm (or 0.75 meters, because 1 m = 100 cm) to the right is 20.0 N * 0.75 m * 1 = 15 Joules.
#SPJ12
Answer:
Step-by-step explanation:
We have been given a function:
We will compare it with the genral equation which is:
Where, a is amplitude and period of function is
In given equation a is -3 and b is 4
So, period of the given equation is:
Yo can look at the graph in the attachment.
The a is the amplitude and the period of the function is
We have been given a function
We will compare it with the general equation which is
Where a is amplitude and period of the function is
In the given equation a is -3 and b is 4
So, the period of the given equation is:
You can look at the graph.
To learn more about the sin wave visit:
#SPJ2
What should the radius of the circular top and bottom be?