Describe what happens if you are riding a skateboard and hit something like a curb with the front wheels.
Answers
If you are riding a skateboard and hit something like a curb with the front wheels then the skateboard would stop due to the friction offered by the club but your body would fall forward due to the effect of that inertia.
What is Newton's first law?
According to Newton's first law, until pushed to alter its condition by the intervention of an external force,
Every object will continue to be at rest or in uniform motion along a single direction until/unless some external force is applied.
When the front wheels of a skateboard collide with something like a curb, then the skateboard will halt because of the friction created by the object, but your body will fall forward as a result of the inertia.
Learn more about Newton's First Law here, refer to the link;
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Related Questions
What is the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water?
The light bulb in your room is not very bright. You want to use a concave mirror to direct its illumination into a tight, parallel beam of light for reading. The radius of curvature of the mirror is 30 centimeters. At what distance from the mirror should you place the light bulb to produce this parallel light beam
A quantity of a gas is an absolute pressure of 400 K PA in the absolute temperature of 110° Kelvin when the temperature of the gas is raised to 235° Kelvin what's the new pressure of the gas?
Assuming 70% of Earth's surface is covered in water at an average depth of 2.5 mi, estimate the mass of the water on Earth in Kilograms.
Answers
Answer: h =1.22 m
Explanation:
from the question we were given the following
mass of performer ( M1 ) = 77 kg
length of cable ( R ) = 3.65 m
mass of costar ( M2 ) = 55 kg
maximum height (h) = ?
acceleration due to gravity (g) = 9.8 m/s^2 (constant value)
We first have to find the velocity of the performer. From the work energy theorem work done = change in kinetic energy
work done = 1/2 x mass x ( (final velocity)^2 - (initial velocity)^2 )
initial velocity is zero in this case because the performer was at rest before swinging, therefore
work done = 1/2 x 77 x ( v^2 - 0)
work done = 38.5 x ( v^2 ) ......equation 1
work done is also equal to m x g x distance ( the distance in this case is the length of the rope), hence equating the two equations we have
m x g x R = 38.5 x ( v^2 )
77 x 9.8 x 3.65 = 38.5 x ( v^2 )
2754.29 = 38.5 x ( v^2 )
( v^2 ) = 71.54
v = 8.4 m/s ( velocity of the performer)
After swinging, the performer picks up his costar and they move together, therefore we can apply the conservation of momentum formula which is
initial momentum of performer (P1) + initial momentum of costar (P2) = final momentum of costar and performer after pick up (Pf)
momentum = mass x velocity thereforethe equation above now becomes
(77 x 8.4) + (55 x 0) = (77 +55) x Vf
take note the the initial velocity of the costar is 0 before pick up because he is at rest
651.3 = 132 x Vf
Vf = 4.9 m/s
the performer and his costar is 4.9 m/s after pickup
to finally get their height we can use the energy conservation equation for from after pickup to their maximum height. Take note that their velocity at maximum height is 0
initial Kinetic energy + Initial potential energy = Final potential energy + Final Kinetic energy
where
kinetic energy = 1/2 x m x v^2
potential energy = m x g x h
after pickup they both will have kinetic energy and no potential energy, while at maximum height they will have potential energy and no kinetic energy. Therefore the equation now becomes
initial kinetic energy = final potential energy
(1/2 x (55 + 77) x 4.9^2) + 0 = ( (55 + 77) x 9.8 x h) + 0
1584.7 = 1293 x h
h =1.22 m
Answers
Answer:
yes
Explanation:
The solubility of glucose at 30°C is
125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water at 30°C. Explain your classification, and describe how you could increase the amount of glucose in the solution without adding more glucose.
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A solar eclipse might be observed from Earth when the moon is in the newmoon phase.
What would be observed from the Moon while Earth is experiencing a solar eclipse?
During the lead-up to a solar eclipse from the Moon, a viewer on the Moon would see the Sun approach the dark disk of Earth, with the planet's nightside facing the Moon. Earth's atmosphere would be lit from behind, creating a reddish ring around the planet that would glow brighter as the eclipse proceeded.
When can you see the solar eclipse?
We will finally see a total solareclipse on April 8, 2024, in North America and Central America. The total phase will be visible from Mexico, the central United States, and eastern Canada. Another eclipse in 2024, an annular one, will take place on Oct. 2.
Learn more about the solar eclipse here brainly.com/question/1287289
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The mass needs to be reduced.
The distance that the force is exerted needs to increase.
The mass needs to be increased.
Answers
Answer:
The distance that the force is exerted need to increase
Explanation:
Work is defined as the product of the force and distance in the direction of applied force.
W = Fd ………………. (i)
Equation (i) shows that work done can be changed by changing either force or distance. If you reduce force, you have to increase distance accordingly to keep work done constant.
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C. virtual image.
Answers
Answer:
Explanation:
Suppose two clowns on skateboards are standing motionless on a smooth surface 2.0 m apart. Clown B tosses a 5.0 kg medicine ball to Clown A. After the throw the medicine ball is traveling with a speed of 10 m/s. What is the resulting velocity of Clown B after throwing the ball? *Indicate which direction is positive.
By momentum conservation
Momentum of ball = 10 . 5 = 50 kg m/s
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