Answer:
24,360
Step-by-step explanation:
30P3 = 30!/(30-3)! = 30·29·28 = 24,360
Answer:
Compute the permutation. 30 P 3
Answer options: 9,000 27,000 24,360
Step-by-step explanation:
The factorial function (symbol:!) Means that descending numbers are multiplied. 30 P 3.
30! = 30 x 29 x 28 =24,360
The answer is: 24,360
Answer:
12x7y3
----------- = 6x4y3
6x3y
Step-by-step explanation:
In dividing these numbers, you simply subtract 6x from 12x and subtract 3y from 7y because 6x and 3y are both in the denominator. 3 is left alone.
Answer:
80 inches
Step-by-step explanation:
8x10=80
because, lxw
l= length
w= width
Answer:
80
Step-by-step explanation:
im not trying to copy the answer above, im just going to say why its 80
so firstly we have the known dimensions of 10 by 8, so in this case we have 10 rows that each contain 8 units
we can then multiply the 8 units of one row, by the amount of rows there are total (in this case 10) to get the total unit count, or area
8 * 10 = 80
(NOTE: you can use the Asterisk (*) as a multiplication mark as to not get it confused with x as in the variable, as with slash (/) for dividing)
hope this helps with this and other problems, credits to the answer above for doing the initial work :)
0.000000000093
Answer:
your answer for 0.000000000093 would defiantly be 9.3 x 10^-11
Step-by-step explanation: i know this cause i took the test and got it wright
(c) Give a function t = f −^1 (w) relating the time to the width of the surface of the water. Make sure to specify the domain and compute the range too.
Answer:
(a) Let h represents the height of water and w represents the width of the water,
Since, the depth of the water is increasing at a rate of 2 inches per hour,
So, after t hours,
The height of water, h(t) = 2t inches = t/6 ft,
( ∵ 1 foot = 12 inches ⇒ 1 inch = 1/12 ft )
Thus, the distance distance from the centre to the top of the water, d = 9 - h(t) ( see in the diagram )
,
By the Pythagoras theorem,
Since, diameter of the semicircular cross section is 18 ft,
So, 0 ≤ w ≤ 18,
i.e Range = [0, 18]
Also, w will be defined if 108t - t² ≥ 0
⇒ (108 - t)t ≥ 0,
⇒ 0 ≤ t ≤ 108
i.e Domain = [0, 108]
(b) If w = 6,
By using quadratic formula,
Hence, After 3.1 hours or 104.9 hours will the surface of the water have width of 6 feet.
(c)
For 0 ≤ w ≤ 18,
0 ≤ t ≤ 108,
So, Domain = [0, 18]
Range = [0, 108]
The width of the water's surface in a semicircular trough can be represented by the function w=t/3 and its domain is t ≥ 0 and the range is 0 ≤ w ≤ 6. To have a 6 feet wide surface, thus, it would take 18 hours. The inverse function is t=3w, with a domain of 0 ≤ w ≤ 6 and range of t ≥ 0.
Given that the depth of the water is increasing at a rate of 2 inches per hour in a semicircular trough, we can convert this rate to feet per hour by dividing by 12, getting an increase of 1/6 feet per hour.
(a) We can express the width of the surface of the water as a function of time. We consider the cross-section of the trough is a semicircle. So, the radius of the water's surface will be the height of water, and this height increases at 1/6 feet per hour. Therefore, the width of the surface of water, w=2r=2*1/6t=t/3. The domain of the function is t ≥ 0 and the range is 0 ≤ w ≤ 6.
(b) We set w=6 in the function w=t/3 and solve for t. We get t=3*6=18 hours.
(c) The inverse function of w=t/3 is t=3w. The domain of the inverse function is 0 ≤ w ≤ 6 and the range is t ≥ 0.
#SPJ11
kilometers high is Niagara Falls?
Answer:
0.056 kilometers
Step-by-step explanation: