Derek found a function that approximately models the population of iguanas in a reptile garden, where x represents the number of years since the iguanas were introduced into the garden.i(x) = 12(1.9)^x


Rewrite this function in a form that reveals the monthly growth rate of the population of iguanas in the garden. Round the growth factor to the nearest thousandth.

Answers

Answer 1
Answer:

Answer:

i(x)=12 * (1+(0.9)/(12))^(12x) and growth rate factor is 0.075

Step-by-step explanation:

The function that models the population of iguanas in a reptile garden is given by i(x)=12 * (1.9)^(x), where x is the number of years.

Since, i(x)=12 * (1.9)^(x)

i.e. i(x)=12 * (1+0.9)^(x).

Therefore, the monthly growth rate function becomes,

i.e. i(x)=12 * (1+(0.9)/(12))^(x * 12).

i.e. i(x)=12 * (1+(0.9)/(12))^(12x).

Hence, the monthly growth rate is i.e. i(x)=12 * (1+(0.9)/(12))^(12x).

Also, the growth factor is given by (0.9)/(12) = 0.075.

Thus, the growth factor to nearest thousandth place is 0.075.


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The product of two numbers is 450. the first number is half the second number. which equation can be used to find x, the greater number? = 450 225x2 = 0 x2 = 450 450x2 = 0

Answers

Answer:

let the two number be x and y.

Given: the product of two numbers is 450.

then:  x* y =450                        ......[1]

Also from the given condition that; the first number is half the second number. Also, x>y.

i.e, y=(1)/(2)x

Substitute this in equation [1];

x * (1)/(2)x =450

or

(1)/(2)x^2 = 450                  [∴x^a * x^b =x^(a+b)]

Multiply both sides by 2; we get

x^2 =450 * 2

or

x^2=900

or

x=√(900) =30

Now, substitute this x value in [1], to solve for y;

30 * y=450

Divide by 30 from both the sides, we get;

y = (450)/(30)=15

Therefore, the equation (1)/(2)x^2 = 450 which can be used to find the value of x.

The greater number is x = 30.

The equation is used to find x is;

\rm x^2=900

The value of the greater number x is 30.

Given

The product of the two numbers is 450.

The first number is half the second number.

Let the first number be x and the second number be y.

The product of the two numbers is 450.

\rm x* y = 450

The first number is half the second number.

\rm x = (1)/(2) y

Substitute the value of x in equation 1 from equation 2

\rm x * y = 450\n\nx * (1)/(2)x = 450\n\nx^2 = 450 * 2\n\nx^2=900\n\nx=30

Substitute the value of x in equation 1

\rm x* y=450\n\n30 * y = 450\n\ny = (450)/(30)\n\ny = 15

Hence, the value of the greater number x is 30.

To know more about Equation click the link given below.

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Write 0.31¯¯¯¯¯ as a simplified fraction. Enter your answer as a simplified fraction, formatted like this: 42/53. A) 31/100 B) 31/10 C) 31/99 D) 31/33

Answers

The answer of ‘Write 0.31 as a simplified fraction’ is A) 31/100

Tea from Britain costs $2.50 to produce. It is sold in America at a price of $3.50 (to make a profit of $1.00) Tea in America costs $3.00 to produce. It is sold at a price of $4.00 (to make a profit of $1.00) If there is a 50% Tariff on tea, who would you buy your tea from?

Answers

Answer:

I would buy my tea from Britain.

There are 24 men in a room¼ of the men are wearing red shirts
½ of the men are wearing green shirts
The remaining men are wearing blue shirts
Workout the number of men that are wearing blue shirts​

Answers

Answer:

6

Step-by-step explanation:

1/4= 6 men

1/2=12 men

therefore 24-12-6=6 men

16/4 x 11/5

what is this answer ?

Answers

Answer:

44x/5

Step-by-step explanation:

Answer: what method are you using to solve this?

Step-by-step explanation:

Write an equation of a circle whose center is (-3,2) and whose diameter is 10

Answers

The\ equation\ of\ a\ circle:(x-a)^2+(y-b)^2=r^2\n\n(a;\ b)-the\ coordinates\ of\ the\ cener;\ r-the\ radius\n-------------------------------\nThe\ center\ (-3;\ 2)\to a=-3;\ b=2\na\ diameter\ d=2r\ therefore\ r=(1)/(2)d\to r=(1)/(2)\cdot10=5\n\nAnswer:\n\boxed{(x-(-3))^2+(y-2)^2=5^2}\to\boxed{(x+3)^2+(y-2)^2=25}
(x-x_1)^2+(y-y_1)^2=r^2\n(x_1,y_1) - \text{ center}\n\nr=\frac{\text{ diameter}}{2}=(10)/(2)=5\n\n(x-(-3))^2+(y-2)^2=5^2\n\boxed{(x+3)^2+(y-2)^2=25}