Answer:
0.172 mol·L⁻¹
Step-by-step explanation:
1. Write the chemical equation for the reaction.
HBr + LiOH ⟶ LiBr + H₂O
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2. Calculate the moles of LiOH
c = n/V Multiply each side by V
n = Vc
V = 0.0375 L
c = 0.215 mol·L⁻¹
Moles of LiOH = 0.0375× 0.215
Moles of LiOH = 8.062 × 10⁻³ mol LiOH
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3. Calculate the moles of HBr
1 mol HBr ≡ 1 mol LiOH
Moles of HBr = 8.062 × 10⁻³× 1/1
Moles of HBr = 8.062 × 10⁻³ mol HBr
===============
4. Calculate the molar concentration of the HBr
V = 47.0 mL = 0.0470 L
c = 8.062 × 10⁻³/0.0470
c = 0.172 mol·L⁻¹
The molarity of the HBr solution is 0,172 M.
The neutralization reaction between LiOH and HBr is the following:
HBr(aq) + LiOH(aq) → LiBr(aq) + H₂O(l)
Answer:
erosion
Explanation:
B.diamonds
C.wood
D.fossil fuels