MATHEMATICS MIDDLE SCHOOL

If x = 1 is a zero of the polynomial x3 – 7x + 6, find the other two zeroes.

Answers

Answer 1

Answer:

Answer:

x = - 3, x = 2

Step-by-step explanation:

Since x = 1 is a zero then (x - 1) is a factor of the polynomial

dividing x³ - 7x + 6 ÷ (x - 1)

= (x - 1)(x² + x - 6)

= (x - 1)(x + 3)(x - 2)

equating (x + 3)(x - 2) = 0 gives the other zeros

equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x - 2 = 0 ⇒ x = 2

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How many different values can an algebraic expression like 5+(x+2)2 have?

Answers

it depend on what question an algebric can have as many but depends???

Which inequality is false?A.
–8 > –1

B.
5 < 10

C.
–5 < –2

D.
14 > –9

Answers

A) $-8 \ \textgreater \ -1$ is false. There is no solution.

B) $5 \ \textless \ 10$ is true. There are infinite solutions.

C) $-5 \ \textless \ -2$ is true. There are infinite solutions.

D) $14 \ \textgreater \ -9$ is true. There are infinite solutions.

the answer is A. -8 > -1

because -8 is less than -1

If 125/27 gives 4.629629629 on a calculator how would it be expressed as an exact answer ?

Answers

4.62

Hope this helps!:D

I need some help with fractions

Answers

for #3, 7 out of the eight pieces are shaded... 7/8

Now, we need however many out of 16, so you need to multiply 7 and 8 both by 2, 14/16... so you should shade 14 out of the 16 pieces

Hope this helped!!! :)

Help Please! What is the simplest form of the product? ^3 sqrt 4x^2 * ^3 sqrt 8x^7

Answers

Answer:

$2x^3\sqrt[3]{4}$

Step-by-step explanation:

We have been given an expression $\sqrt[3]{4x^2} *\sqrt[3]{8x^7}$ and we are asked to find the product of our given expression.

Using exponent rule of power to powers $(a^(mn)=(a^m)^n)$ we can write $8x^7$ as $(2x^2)^3x$ and $4x^2=(2x)^2$ .

Upon substituting these values in our expression we will get,

$\sqrt[3]{4x^2} *\sqrt[3]{(2x^2)^3x}$

Using exponent rule $\sqrt[n]{x^m} =x^{(m)/(n)}$ we will get,

$\sqrt[3]{4x^2} *2x^2\sqrt[3]{x}$

Multiplying $\sqrt[3]{x}$ by $\sqrt[3]{4x^2}$ we will get,

$\sqrt[3]{4x^3} *2x^2$

Using exponent rule $\sqrt[n]{x^m} =x^{(m)/(n)}$ we will get,

$x\sqrt[3]{4}*2x^2$

$x*2x^2\sqrt[3]{4}$

$2x^3\sqrt[3]{4}$

Therefore, the simplest form of the product of our given expression will be $2x^3\sqrt[3]{4}$ .

Answer:

$2x^(3) * \sqrt[3]{4}$

Step-by-step explanation:

Julie is going to the store to buy candles. Small candles cost $2.50 and large candles cost $4.00. She needs to buy a mix of at least 25 candles, and she can spend no more than $85. How many of each type of candle can she buy? Use a sentence to describe how many candles you buy.

Answers

20 large candles because $4*20 candles=$80
2 small candles because $2.50*2=$5
$80+$5=$85

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