a missile is moving 1350 m/s at a 25.0 deg angle. it needs to hit a target 23,500 m away in 55.0 deg direction in 10.20 s. what is the magnitude of its final velocity?

Answers

Answer 1
Answer:

In this question we have given

velocity of missile=1350m/s

angle at which missile is moving=25degree

distance between missile and targets=23500m

angle between target and missile=55degree

time=10.2s

To find the final velocity of missile we will first find the acceleration required

Let x be the horizontal component of distance

x - vertical component of distance

t-time

ax- horizontal component of acceleration

ay-Vertical component of acceleration

Vx-horizontal component of velocity

Vy-Vertical component of velocity


horizontally: x = Vx*t + ½*ax*t²  

23500m * cos55.0º = 1350m/s * cos25.0º * 10.20s + ½ * ax * (10.20s)²  

ax = 19.2 m/s²  

V'x = Vx + ax*t = 1350m/s * cos25.0º + 19.2m/s² * 10.20s = 1419 m/s  

similarly vertically:

y = Vy*t + ½*ay*t² 

23500m * sin55.0º = 1350m/s * sin25.0º * 10.20s + ½ * ay * (10.20s)²  

ay = 258 m/s²  


V'y = Vy + ay*t = 1350m/s * sin25.0º + 258m/s² * 10.20s = 3204 m/s  

Therefore

V = √(V'x² + V'y²) = 3504 m/s  

therefore magnitude of final velocity of missile=3504m/s


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Answers

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Answers

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A picture of a concave lens and the ray diagram produced by it can be seen in attachment. As it can observed, the concave lens (also called diverging lens) is wider at the edges and narrow at the centre (so, it curves inward), and it can also be seen that the lens diverges the incoming light rays.


A concave lens diverges light and curves inward is the statement which

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This type of lens is used to treat short-sightedness and has at least one of

its surface curving inward. This helps it to spread out light rays so as to

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It has a high degree of diffraction and is the reason why option A was

chosen as it's the most appropriate choice.

Read more about Concave lens here brainly.com/question/3140453

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Answers

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Answers

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Answers

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