Answer:
Explanation:
From the given data on the table, I can easily say my weight is a function of the acceleration due to gravity at anywhere in the universe.
Weight is given as
W = mg
m is the mass and g is the acceleration due to gravity.
Weight for a mass of 65kg would be the heighest on the surface of jupiter and it would be lowest on merury and mars due to their low value of g.
Answer:
The conclusion is that the mass is independent of gravity. However, the weight depends on the gravity value.
Explanation:
We have a girl with a mass of 65 kg. The picture has the gravity value for different planets. Weight (W) of a body is the product between the mass (M) and the gravity (g).
W = M*g.
According to the information we can mention that the weight of the girl will vary in all the planets. The highest weight will be for the highest gravity value of Jupiter with 25.9 m/s2. The lowest weight will be for Mercury and Mars with a gravity value of 3.7 m/s2.
It is important to mention that the mass of the girl will be the same in all the planets. However, the weight will vary according to the gravity variations.
Finally, The conclusion is that the mass is independent of gravity. However, the weight depends on the gravity value.
For n = 3, the possible orbitals are:
3s orbital: The 3s orbital is spherical in shape and can hold up to 2 electrons.
3p orbitals: The 3p orbitals have a dum/bb/ell shape and consist of three individual orbitals: 3px, 3p/y, and 3pz. Each of these orbitals can hold up to 2 electrons, so the total capacity of the 3p sublevel is 6 electrons.
3d orbitals: The 3d orbitals have complex shapes and consist of five individual orbitals: 3dxy, 3dxz, 3dyz, 3dx2-y2, and 3dz2. Each of these orbitals can also hold up to 2 electrons, resulting in a total capacity of 10 electrons for the 3d sublevel.
In summary, for n = 3, the possible orbitals are 3s, 3p (3px, 3py, 3pz), and 3d (3dxy, 3dxz, 3dyz, 3dx2-y2, 3dz2).
Learn more about orbitals at
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Answer:The n = 3 shell, for example, contains three subshells: the 3s, 3p, and 3d orbitals. There is only one orbital in the n = 1 shell because there is only one way in which a sphere can be oriented in space.
Explanation:hope this helps:D
(1) O2-
(2) S2-
(3) Se2-
(4) Te2-
Answer:
Option-1 (O²⁻) is the correct answer.
Explanation:
All given anions contains same charge. So, we can ignore the effect of charge on these anions.
As we know all given compounds belongs to same group (Group 6) in periodic table. And from top to bottom along the group the elements are placed as,
Oxygen O
Sulfur S
Selenium Se
Tellurium Te
Hence, moving from top to bottom along the group the number of shells increases. And with increase in number of shell the atomic or ionic radii increases. As Oxygen is present at the top of the group, therefore, it has the smallest radius due to less number of shells.
O²⁻ ion has the smallest radius
In an atom there are levels of energy in the shell and sub shell.
This energy level is expressed in the form of electron configurations.
Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d and f. The maximum number of electrons for each sub shell is
Charging electrons in the sub shell uses the following sequence:
1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.
Each sub-shell also has an orbital shown in the form of a square in which there are electrons symbolized by half arrows
The atomic radius shows the distance of the atomic nucleus to the electrons in the outer shell
From left to right in the period system the atomic radius gets smaller, while from one group from top to bottom the atomic radius gets longer
The more the number of shells the atom has, the radius of the atom getting longer, but if the number of shells is the same, the larger atomic number has shorter radius because the core charge is greater so that the attraction of the nucleus to the electrons is stronger
In the ions
(1) O²⁻
(2) S²⁻
(3) Se²⁻
(4) Te²⁻
All of these ions are ions from the elements of the VIA group in the periodic system. This group consists of oxygen (O), sulfur (S), selenium (Se), tellurium (Te), and polonium (Po).
The periodic system is arranged in the order of atomic numbers, whereas in this VIA group from top to bottom, the atomic number gets bigger
Atomic Number: 8
Electron configuration: 1s² 2s² 2s⁴ (number of shells 2)
Atomic Number: 16
Electron configuration: [Ne] 3s² 3p⁴ (number of shells 3)
Atomic Number: 34
Electron configuration: [Ar] 3d¹⁰ 4s²4p⁴ (number of shells 4)
Atomic Number: 52
Electron configuration: [Cr] 4d10 5s² 5p⁴ (number of shells 5)
From the configuration of the electron shows that the lower the shell owned by the elements of the VIA group the greater (from 2 to 5) so that the radius is also getting longer/bigger
Because what is being asked is the radius of the ion, the electron configuration of each element is equally reduced by 2 electrons, but the number of shells remains the same
(1)O²⁻
Electron configuration: 1s² 2s² 2s²
(2) S²⁻
Electron configuration: [Ne] 3s² 3p²
(3) Se²⁻
Electron configuration: [Ar] 3d¹⁰ 4s²4p²
(4) Te²⁻
Electron configuration: [Cr] 4d¹⁰ 5s² 5p²
Because the amount of shell from the Oxygen ion is the smallest, the radius of the O²⁻ is also the smallest
electron affinity
Identify the group number in the periodic table
the charge on each ion in the compounds
Keywords: element, group 6A, the smallest radius