The altitude of the triangle whose base is 3 cm longer than its altitude is 7cm.
Triangle is a plane figure with three straight sides and three angles such that the sum of the angles is 180°.
Given is a triangle whose base is 3cm longer than its altitude. The area of the triangle is 35 cm².
Assume that the altitude of the triangle is 'a' cm.
The area of a tringle is given by -
A [T] = 1/2 x base x height.
Now,
Altitude of triangle = a cm
Base of triangle = (a + 3) cm
Substituting the values in the formula of area, we get -
A [T] = 1/2 x base x height
A [T] = 1/2 x a x (a + 3)
a(a + 3) = 35 x 2
a(a + 3) = 70
a² + 3a - 70 = 0
On solving the above quadratic equation, you will get two values of x -
a = - 10 and a = 7
Altitude cannot be negative. Therefore, the altitude of the triangle is 7 cm.
Therefore, the altitude of the triangle whose base is 3 cm longer than its altitude is 7cm.
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Total number of rotten mangoes in the bag = 6
Total number of good mangoes in the bag = 24
Fraction of the rotten mangoes to the total mangoes.
Total number of mangoes in the bag = Total number of rotten mangoes + Total number of good mangoes
➺
➺
Now,
Fraction =
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Therefore, the fraction of the rotten mangoes to the total mangoes is .
Answer:
6/24
Step-by-step explanation:
It is 1/4 in simplest form
The equation h = vt - 16t² is solved for v will be given as v = (h + 16t²) / t.
The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.
Making anything easier to accomplish or comprehend, as well as making it lessdifficult, is the definition of simplification.
The equation is given below.
h = vt - 16t²
Simplify the equation for v, then the equation is written as,
h = vt - 16t²
vt = h + 16t²
v = (h + 16t²) / t
The equation h = vt - 16t² is solved for v will be given as v = (h + 16t²) / t.
More about the solution of the equation link is given below.
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