1.2 Multiply (3-2p) by (3-2p)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (3-2p) and the exponents are :
1 , as (3-2p) is the same number as (3-2p)1
and 1 , as (3-2p) is the same number as (3-2p)1
The product is therefore, (3-2p)(1+1) = (3-2p)2
A 48°
B (6x−28)°
C (2x)°
Find the value of x. Then find the measures of angles B and C.
Enter your answers in the boxes.
x =
m∠B=
m∠C=
The required measure angles B and C of are 92° and 40° and value of x = 25.
Given,
The measures of the angles in △ABC are 48°, (6x-28)° , (2x)°.
We have to find,
The value of x Then measures of angles B and C.
According to the question,
The sum of all internal angles in a triangle is always equal to 180°.
48° + 6x − 28° + 2x° = 180
8x + 20 = 180
8x = 180 - 20
8x = 160
x = 20
The required value of x = 20.
Then, The required angle are,
6x - 28 = 6(20) - 28 = 92°
And 2x = 2(20) = 40°
The required angles are 92° and 40° .
For more information about Triangle click the link given below.
1/11^12
1/11^4
11^4
11^12
2(10 + 15)
2(2 + 5)
2(20 + 5)
False in a triangle 2 sides are the same and one is different.
A triangle can be formed with side lengths 2 in, 3 in, and 6 in.
According to the question
A triangle can be formed with side lengths 2 in, 3 in, and 6 in.
For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.
The sum of two smaller sides is
So, 5 inches < 6 inches
Hence, False in a triangle 2 sides are the same and one is different.
To know more about Triangles click the link given below.