Answer:
First question:
The graph of has a vertical asymptote at x = and a horizontal asymptote at y =
Second question:
The graph of equation has a horizontal asymptote at y = -3 ⇒ C
Step-by-step explanation:
The vertical asymptotes will occur at the values of x for which make the denominator is equal to zero
The horizontal asymptotes will occur if:
First question:
∵
- To find the vertical asymptote equate the denominator by 0
to find the value of x
∵ The denominator is 2 - 3x
∴ 2 - 3x = 0
- Add 3x to both sides
∴ 2 = 3x
- Divide both sides by 3
∴ = x
∴ The graph has a vertical asymptote at x =
To find the horizontal asymptote look at the highest degree of x in both numerator and denominator
∵ The denominator and the numerator has the same degree of x
- Divide the coefficient of x of the numerator and denominator
∵ The coefficient of x in the numerator is -2
∵ The coefficient of x in the denominator is -3
∵ -2 ÷ -3 =
∴ The graph has a horizontal asymptote at y =
The graph of has a vertical asymptote at x = and a horizontal asymptote at y =
Second question:
The graph has a horizontal asymptote at y = -3
means the numerator and the denominator has same highest degree and the coefficient of the highest degree in the numerator divided by the coefficient of the highest degree in the denominator equal to -3
∵ In answer A the quotient is 1 because x up and down have
coefficient 1
∵ In answer B the quotient is because the coefficient of x
up is 1 and down is -3
∵ In answer D the quotient is -1 because the coefficient of x
up is 3 and down is -3
∵ In answer C the quotient is -3 because the coefficient of x up
is -3 and down is 1
∴ The graph of equation has a horizontal asymptote at y = -3
b(n)=4−6(n−1)
Answer:
If you wish to find any term (also known as the {n^{th}}n
th
term) in the arithmetic sequence, the arithmetic sequence formula should help you to do so. The critical step is to be able to identify or extract known values from the problem that will eventually be substituted into the formula itself.
Step-by-step explanation:
y=4.9x-1.64
The approximate solution to the system is (____,____).
The approximatesolution to the system is (1.23,4.39).
Graphical method, or Geometric method, allows solving simple linear programmingproblems intuitively and visually. This method is limited to two or three problems decision variables since it is not possible to graphically illustrate more than 3D.
For this case we have the following system of equations:
y=-0.25x+4.7
y=4.9x-1.64
The above linear system equation can be solved using graph, using
1) The solution of given system of equations can be determined by the intersecting point of equation.
2) Then the solution will be an ordered pair, form (x, y).
Now considering the above two points, the graph is attached below:
look at the intersecting point here, the x- coordinate is 1.23 and the ycoordinate is approx. 4.40.
Hence, the approximate solution to the system is (1.23,4.39)
Learn more about graph here:
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Answer:
2.365 unit far away the center are the foci located.
Step-by-step explanation:
Given : If the eccentricity of an ellipse is 0.43 and the length of its major axis is 11 units.
To find : How far from the center are the foci located?
Solution :
The eccentricity of an ellipse is defined as
Where, e is the eccentricity
c is the distance from center to focus
a is the distance between focus to vertex.
We have given,
Eccentricity of an ellipse is 0.43 i.e. e=0.43
The distance between focus to vertex is the half of the length of its major axis.
i.e.
Substitute in the formula,
Therefore, 2.365 unit far away the center are the foci located.