Is adding sugar to lemonade a chemical or physical change

Answers

Answer 1
Answer: physical.. think of it as a person putting on weight.. adding weight, but still a person. adding sugar, but still lemonade.
Answer 2
Answer: That's a physical change since nothing's really happening except for the flavor. Only the flavor changed cause you added something, but it's not a chemical

Related Questions

The resultant resistance of two resistance wires in series combination is 108 ohm and in parallel combination is 24 ohm. find the value of individual resistance.
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Which statement is true about the energy of electromagnetic radiation? A.the frequency of the emmited radiation is inversely proportional to its energy. B.the frequency of the emitted radiation is directly proportional to its energy C.the wavelength of the emitted radiation is directly proportional to its energy. D.the amplitude of the emitted radiation is inversely proportional to its energy.

Answers

The frequency of the emitted radiation is directly proportional to its energy 

Answer: Option (B) is the correct answer.

Explanation:

The radiation in which waves of electromagnetic field travel or propagate through the space and carries electromagnetic radient energy is known as electromagnetic radiation.

The relation between energy and frequency is as follows.

                    E = h \nu  ............ (1)

where,      E = energy

                h = plank's constant

           \nu = frequency

Therefore, the frequency of the emitted radiation is directly proportional to its energy.

Also, frequency is proportional to c over wavelength. The relation is as follows.

                \nu = (c)/(\lambda) ........ (2)

where,      \nu = frequency

                         c = speed of light

                     \lambda = wavelength

Placing the value of frequency from equation (2) to equation (1) as follows.  

                          E = (hc)/(\lambda)

Thus, the wavelength of the emitted radiation is inversely proportional to its energy.

Two vertical springs have identical spring constants, but one has a ball of mass m hanging from it and the other has a ball of mass 2m hanging from it. Part A If the energies of the two systems are the same, what is the ratio of the oscillation amplitudes?

Answers

Answer:

(A_1)/(A_2)=1

Explanation:

given,

two identical spring have identical spring constant

mass 'm' is hanging on one spring and mass of '2m' on another wall.

energy of the two system is same

energy of the system having mass 'm'

E = (1)/(2)m\omega_1^2A_1^2

energy of the system having mass '2m'

E = (1)/(2)(2m)\omega_1^2A_1^2

now, Energy are same

(1)/(2)m\omega_1^2A_1^2= (1)/(2)(2m)\omega_1^2A_1^2

(A_1^2)/(A_2^2)=(2\omega_2^2)/(\omega_1^2)

we know k = mw^2

(A_1)/(A_2)=\sqrt{\frac{2(k)/(m_2)}{{(k)/(m_1)}}

(A_1)/(A_2)=\sqrt{(2m_1)/(m_2)}

(A_1)/(A_2)=\sqrt{(2m)/(2m)}

(A_1)/(A_2)=1

Anyone knows what this is?

Answers

I think it is D.) “Cycles around” but I am not positive.

A graph depicts force versus position. What represents the work done by the force over the given displacement?A. The work done is equal to the product of the maximum force times the maximum position.
B. The work done is equal to the area under the curve.
C. Work cannot be determined from this type of graph.
D. The work done is equal to length of the curve.
E. The work done is equal to the slope of the curve.

Answers

Work = (force) x (distance)

With a force/distance graph, the work is the area under the graph.

If the graph is curved, broken, or some other screwy shape that makes it difficult to
get the area in any simple way, then work is the integral of the function represented
by the graph.

Final answer:

The work done by a force over a given displacement, as represented in a force versus position graph, is equal to the area under the curve.

Explanation:

In a force versus position graph, the work done by the force over the given displacement is represented by the area under the curve. The work done is the integral of the force with respect to displacement which, in a graphical representation, translates to the area under the curve of the force versus position graph. For example, if the force is constant, the graph will be a rectangle, and the work done will be the product of force (height of the rectangle) and displacement (width of the rectangle). If the force is variable, the area under the curve might need to be calculated by dividing it into small sections and summing up their areas.

Learn more about Work and Energy here:

brainly.com/question/16987255

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If earth did not rotate what would happen to the global winds

Answers

If the Earth didn't rotate, winds would travel either North or South due to differences in temperature and pressure at different latitudes.

Technician A says that an oxygen sensor can have​ one, two,​ three, four, or more​ wires, depending on the style and design. Technician B says that if the exhaust has little​ oxygen, the voltage of the oxygen sensor will be close to 1 volt​ (1000 mV) and close to zero if there is high oxygen content in the exhaust. Who is​ right?

Answers

Answer:

Both technicians A and B are right.

Explanation:

-The most common application is to measure the exhaust-gas concentration of oxygen.The probe typically has four wires attached to it: two for the lambda output, and two. The number of wires depends on design and style.

-An oxygen sensor will typically generate up to about 0.9 volts(\approx 1.0V) when the fuel mixture is rich and there is little unburned oxygen in the exhaust. When the mixture is lean, the sensor's output voltage will drop down to about 0.1( \approx 0.0V)volts