Answer is: D. sodium and sulfur.
When the electronegativity difference is greater, the bond polarity is increasing..
Electronegativity (χ) is a property that describes the tendency of an atom to attract a shared pair of electrons.
Atoms with higher electronegativity attracts more electrons towards it, electrons are closer to that atom.
Δχ(Na-S) = 2.6 - 0.95 = 1.655; electronegativity difference between sodium and sulfur.
Ionic bond is the electrostatic attraction between oppositely charged ions (cations and anions).
Sodium is metal (forms cation) and sulfur is nonmetal (forms anion).
Answer:
Se + 2e- => Se-2
Explanation:
Ions are electrically charged particles, formed due to the gain or loss of electrons by an atom.
There are two types of ions cations and anions. An element that loses their electrons and forms positive ions are cations while metals and element that gains one or more electrons and forms negative ions are anions.
Selenium is an atom with atomic number 34 and represented as Se. The electronic configuration of Se is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p4. Selenium will gain 2 more electrons to complete it p orbital and form an ion Se-2.
The equation is as below:
Se + 2e- => Se-2
Which equation represents the oxidation half reaction?
(1) Zn(s) + 2e– → Zn2+(aq)
(2) Zn(s) → Zn2+(aq) + 2e–
(3) Cu2+(aq) → Cu(s) + 2e–
(4) Cu2+(aq) + 2e– → Cu(s)
Answer: Option (2) is the correct answer.
Explanation:
Oxidation is the process in which there is loss of electrons or increase in oxidation number of the element.
Whereas reduction is the process in which there is gain of electrons or decrease in oxidation number of the element.
For example,
Oxidation-half reaction:
Reduction-half reaction:
Thus, we can conclude that the given equation Zn(s) → Zn2+(aq) + 2e– represents the oxidation half reaction.
The equation that represents the oxidation half reaction is Zn(s) → Zn2+(aq) + 2e–
Oxidation reaction is the process in which there is loss of electrons or increase in oxidation number of the element.
From all the given half reaction, there is only one reaction with increase in oxidation number;
Zn(s) → Zn2+(aq) + 2e–
Thus, there is increase in oxidation number of 0 to + 2.
Learn more about oxidation number here: brainly.com/question/27239694
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Answer: B
Explanation:
All of your answers look wrong