If 125/27 gives 4.629629629 on a calculator how would it be expressed as an exact answer ?

Answers

Answer 1

Answer: 4.62

Hope this helps!:D

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This is really easy but I’m just dumb. What is the consecutive interior of 7?

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The transversal connecting four and seven is line m angles four and seven are consecutive interior angles the solution is a line that intersects two or more coplanar lines at two different points is called a transversal the transversal connecting two and seven is line p.

The transversal connecting four and seven is line m angles four and seven are consecutive interior angles.

I kinda need help with this i’ve already done all the other questions but this one and i really want these 600 points :( <3

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I think that the answer is A, because in the range, none of the numbers should be the same, and the numbers are all different in choice A

A boat travels 3,600 in 12 minutes.what is the boat speed

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Divide each by 12 to get its speed for one minute. 3,600/12=300 12/12=1. It is going 300?? in 1 minute. Hope this helped!

Can someone please help me with this (if you cant see it just zoom in)

Answers

Option A: $(S R)/(B C)=(R T)/(C A)$

Option C: $\angle R\cong \angle C$

Solution:

Given ΔRST similar to ΔABC.

To determine which statements are true for the given similarity triangles.

Option A: $(S R)/(B C)=(R T)/(C A)$

By the similarity theorem,

If two triangles are similar, then the corresponding angles are equal and the corresponding sides are in the same ratio or proportion.

Therefore, $(S R)/(B C)=(R T)/(C A)$

It is true.

Option B: $\angle S\cong \angle A$

By the similarity theorem, corresponding angles are equal.

∠S is corresponding to ∠B.

So, $\angle S\cong \angle B$ .

That means ∠S is not corresponding to ∠A.

Therefore, it is false.

Option C: $\angle R\cong \angle C$

By the similarity theorem, corresponding angles are equal.

∠R is corresponding to ∠C.

Therefore $\angle R\cong \angle C$ .

It is true.

Option D: $(S R)/(B C)=(R T)/(AB)$

We already, proved in option A that $(S R)/(B C)=(R T)/(C A).$

Therefore, $(S R)/(B C)\neq (R T)/(AB)$ .

It is false.

Option A and Option C are true.

Hence $(S R)/(B C)=(R T)/(C A)$ and $\angle R\cong \angle C$ .

What is 3.82 rounded to the nearest whole number

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Answer:

Step-by-step explanation:

Step 1: Round to the nearest whole number

3.82

Answer: 4

3.82 rounded to the nearest number is 4

In a sixth-grade class, the ratio of boys to girls is 3:2. How many boys and how many girls could there be in this class? Is there more than one possible answer? Explain.How do you solve?

Answers

Answer:

There could be 6 boys and 4 girls

There are several possible answers.

Step-by-step explanation:

Consider the provided ratio.

the ratio of boys to girls is equal to 3:2, it means that for every 2 girls in the class there will be 3 boys.

Let us assume there are 6 boys in the class.

Then the number of girls would be 4 because the ratio still have to be 3 to 2.

$(6)/(4)= (3)/(2)$

We can use algebra to figure this out or you can use logic.

The boys to girls ratio is 3:2, This can be written as:

$(boys)/(girls) =(3)/(2)$

If we multiply numerator and denominator by 2 we get.

$(boys)/(girls) =(3* 2)/(2* 2)=(6)/(4)$

That means for every 6 boys there are 4 girls, either way the ratio remains the same.

Similarly If we multiply numerator and denominator by 3 we get.

$(boys)/(girls) =(3* 3)/(2* 3)=(9)/(6)$

That means for every 9 boys there are 6 girls, and the ratio remains the same.

So there are more than one possible answer.

Hence, there are several possible answers.

There's an infinite number of possible answers because there might be any multiplication of 3 for boys and any multiplication of 2 for girls. So, for example:

There might be 3 boys and 2 girls.
There might be 6 boys and 4 girls.
There might be 9 boys and 6 girls.
There might be 12 boys and 8 girls.
etc...

In each case the ratio stays the same - 3 : 2.

Of course there probably can't be more than a few dozens of people in one class, but theoretically we can raise the numbers up to infinite.

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