Michelle is building a rectangular landing strip for airplanes .She has material to cover 1/1,500 of a square mile. The landing strip must be 1/6 of a mile long. With the amount of material that has , what is the greatest possible width the land strip, in miles?

Answers

Answer 1

Answer: I think that the missing word here is:
"with the amount of the material that Michelle has"

Let's say that her landing strip is x miles long, then its area would be:

$(1)/(6) *x$

We also know how big it is:

$(1)/(6) *x= (1)/(1 500)$

now, let's multiply both sides by 6:
$(6)/(6) *x= (6)/(1 500)$
$1 *x= (3)/(750)$
$x= (1)/(250)$

So the answer is that it would be $x= (1)/(250)$ miles wide

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Could somebody please answer these three questions with simple yet explanatory answers?

Answers

This is for #11 and #12.
First lets find the lateral area of each triangle. We will use thefollowing formula:-
lateral area = 4 (1/2 * base * slant height)
11. LA = 4 (1/2 * 8cm * 7.5 cm)
= 120 cm^2

12. LA = 4 (1/2 *14 in * 12in ) =
  LA = 336 cm^2
Nowlets find the surface area:-
surface area = lateral area + area of the base
11. S.A. = 120 cm^2+ 8 * 8
  = 120 cm^2 + 64
= 184 cm^2S.A. = 336 cm^2+ 14 * 14
12.   = 336 cm^2 + 196
   = 532 cm^2
LateralArea:-
11. 120 cm^2
12. 336 cm^2
SurfaceArea:-
11. 184 cm^2
12. 532 cm^2

HopeI helped ya!!

Explain it - compare 3 3/22 & 3 2/33. which is greaterI Know:
Multiply the denominator by the whole number then add numerator to that.
Now I have 69/66 & 101/99

THe LCM is 66

what next, which is greater. Thank you

Answers

3 3/22 isn't 69/66.
3 3/22 is like 3+3/22. To sum them,you have to have the same denominator. So 3=66/22. Know you can add them, so 3 3/22=3+ 3/22= 66/22+3/22=69/22.
Same way, 3 2/33= 3+2/33=99/33+2/33=101/33.
Know you have to compare 69/22 with 101/33. For this, you need to get them to the same denominator. So you multiply 69/22 with 3, and 101/33 with 2. Know you have to compare 207/66 with 202/66. Obviously, the first one is bigger, because 207>202. So in the end, 3 3/22> 3 2/33

Some workers at a zoo built a new platform in the water for the seals. The perimieter of theplatform was 60 feet.Which could be the dimensions of the platform for the seals?
36 ft 24 ft
18 ft 12 ft
10 ft 6 ft
12 ft 5 ft

Answers

It would be 18 ft by 12 ft because P=L+L+W+W, which 18+18 is 36 and 12plus 12 is 24. 24 and 36 ft combined is 60 ft.

Find the sum.
(-x - 2y - 4z) + (7x - 6y - 6z)

Answers

−x−2y−4z+7x−6y−6z

=−x+−2y+−4z+7x+−6y+−6z

Combine Like Terms:

=−x+−2y+−4z+7x+−6y+−6z

=(−x+7x)+(−2y+−6y)+(−4z+−6z)

=6x+−8y+−10z

$\bold{6x - 8y -10z}$

Two right triangles on a coordinate plane are similar but not congruent.Each of the legs of both triangle are extended by 1 unit,creating two new right triangles.Are the resulting triangles similar? explain using an example

Answers

Virtually every time you try this stunt, the new triangles
are NOT similar.

Example:

Triangle A₀ . . . legs = 3 and 4; hypotenuse = √25 = 5 .
Triangle B₀ . . . legs = 6 and 8; hypotenuse = √100 = 10 .

Ratio of short legs = 6/3 = 2
Ratio of long legs = 8/4 = 2
Ratio of hypotenuses = 10/5 = 2
The triangles are similar.

Add 1 unit to all legs:

Triangle A₁ . . . legs = 4 and 5; hypotenuse = √41
Triangle B₁ . . . legs = 7 and 9; hypotenuse = √130

Ratio of short legs = 7/4 = 1.75
Ratio of long legs = 9/5 = 1.8
Ratio of hypotenees = √(130/41) = 1.78 .

New triangles are NOT similar.

I think this ONLY works when the original triangles are
congruent, so the ratio of their similarity is 1:1.
When each leg of both triangles is extended by the same
amount, they are still congruent.

But the question stipulates that they are NOT congruent.
So the answer to the question is: No. Never.

They are similar, by SSS. This shows that the sides are all similar but may not be congruent. And they started out similar, and they have the same scale factor. If you had one more angle besides the 90, you would be able to figure out the angles inside and have AA to justify.
Sorry if this is a bad explanation.

8a. History: A typical stone on the lowest level of the Great Pyramid in Egypt was a rectangular prism 5 feet lonng, by 5 feet wide, by 6 feet deep and weighed 15 tons. What is the volume of the average stone? (Note--give volume answer in numbers) *8b. How much did one cubic foot of the stone weigh? (Hint divide the weight by the volume and find the tonage of one cubic foot of the stone)

Answers

Answer:

Answer below!!!

Step-by-step explanation:

NOTE:

(for 8b, you'll put 0.1 ton per cubic feet) which would be the density.

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