Q2 Answer: Experimental = 60%, difference = 10%
Step-by-step explanation:
The prime numbers between 1 and 8 are: 2, 3, 5, and 7.
Theoretical:
Experimental:
Experimental - Theoretical
= 60% - 50%
= 10%
Problem 1
To find the sample mean, we simply add up all the 40 items and then divide by 40
I will add up the values row by row, and then add up the subtotals to get the grand total
row1: 39+31+38+40+29 = 177
row2: 32+33+39+35+32 = 171
row3: 32+27+30+31+27 = 147
row4: 30+29+34+36+25 = 154
row5: 30+32+38+35+40 = 175
row6: 29+32+31+26+26 = 144
row7: 32+26+30+40+32 = 160
row8: 39+37+25+29+34 = 164
Add up the subtotals: 177+171+147+154+175+144+160+164 = 1292
Divide this over 40: 1292/40 = 32.2
So the sample mean is therefore 32.2
-----------------------
To find the proportion of defective items, we count the number of times a value less than 26 shows up. That happens exactly two times. The first in row 4 (at the end of this row) is where a 25 shows up. Another copy of 25 shows up in row 8 (bottom row). There are no other values that are less than 26.
Divide this count (2) over the total sample size (40) and we get 2/40 = 1/20 = 0.05
-----------------------
In summary, 32.2 will go in the first box while 0.05 will go in the second box.
========================================
Problem 2
There are 4 values we want (2,3,5,7) out of 8 total (1,2,3,4,5,6,7,8) so 4/8 = 0.50 = 50% is the theoretical probability
This is the list of values given to us (I broke it up to help make the numbers more readable)
3, 4, 5, 2, 7
1, 3, 7, 2, 6
2, 1, 7, 3, 6
1, 8, 3, 5, 6
Of that list, the primes {3, 5, 2, 7, 3, 7, 2, 2, 7, 3, 3, 5} show up. There are 12 primes in this list out of 20. So the experimental probability is 12/20 = 3/5 = 0.60 = 60%
Therefore, the answer that goes in the "experimental probability" box is 60. The answer that goes in the second box is not 50%. I think your teacher is aiming for "10" to go in the second box because 60% is 10 percentage points higher than 50% (which was the theoretical probability found earlier)
-----------------------
In summary, 60 will go in the first box while 10 will go in the second box.
5 different meats
3 different cheeses
3 different breads
5x3x3 = 15*3 = 45
there are 45 choices
The sandwich shop offers a total of 45 different sandwich combinations based on the given options of meats, cheeses, and breads. Each sandwich consists of one type of each category.
The question asked is related to the concept of combinations in mathematics. It gives a variety of choices for making a sandwich - 5 types of meats, 3 types of cheeses, and 3 types of breads. Assuming that each sandwich will have one meat, one cheese, and one type of bread, we can calculate the total combinations by multiplying the number of options in each category together. Combinations are used when the order of selection does not matter.
So, the total number of sandwich combinations would be 5 (meats) * 3 (cheeses) * 3 (breads) = 45 different sandwich choices.
#SPJ12
Answer:
9530 cg
Step-by-step explanation:
B. 2y + 4 – y = 16
C. 7x + 5 = 4x + 5 + 3x
D. 6y – 2 = 2(y – 1)
The equation 7x + 5 = 4x + 5 + 3x has an Infinite number of solutions. which is the correct answer would be option (C).
The equation is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are equal.
We have to determine which equation has an infinite number of solutions
As per option (C),
⇒ 7x + 5 = 4x + 5 + 3x
Combine comparable terms to simplify both sides of the problem.
You have become left with 7x+5 = 7x+5.
On both sides, subtract 7x.
This gives you 5=5.
Subtraction 5 from both sides
⇒ 0 = 0
Thus, this equation has an Infinite number of solutions.
Hence, the correct answer would be an option (C).
Learn more about the equation here:
#SPJ2
A. Sample: listings in a local newspaper and on an Internet site
Population: all available apartments near the college
B. Sample: all available apartments near the college
Population: all available dormitories near the college
C. Sample: all available dormitories near the college
Population: all available apartments near the college
D. Sample: all available apartments near the college
Population: listings in a local newspaper and on an Internet site
Answer:
Sample: listings in a local newspaper and on an Internet site
Population: all available apartments near the college
This is the correct answer! I just took the test!! Good luck!!
B. 3/20
C.1/10
D.4/153