reflecting, spherical Christmas tree ornament has a diameter of 9.0 cm. A child looks at the ornament from a distance of 12 cm. Describe the image she sees.
Answers
The distance of the image observed by th girl is 2.77 cm.
Focal length of the lens
The focal length of the lens is calculated as follows;
F = R/2
where;
- R is the radius of lens
R = 9 cm/2 = 4.5 cm
F = R/2
F = 4.5/2
F = 2.25 cm
Image distance
The distance of the image observed by th girl is caculated as follows;
1/f = 1/v + 1/u
1/v = 1/f - 1/u
1/v = 1/2.25 - 1/12
1/v = 0.3611
v = 2.77 cm
Thus, the distance of the image observed by th girl is 2.77 cm.
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(9/2)/2 = 2.25 cm
i = 1/(1/f - 1/o)
1/(1/2.25 - 1/12) = 1/2.769 ⇒ 0.36
I believe the image would appear upright.
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Answers
Answer:
Explanation:
The magnitude of the gravitational force between the two spheres is given by:
where
G is the gravitational constant
m1 , m2 are the masses of the two spheres
r is the distance between the centres of the two spheres
Here we have:
m1 = 65 kg is the mass of the first sphere
m2 = 87 kg is the mass of the second sphere
the distance between the centres of the two spheres is equal to the sum of the radius of each sphere and the distance between the surfaces:
r = 0.50 m + 0.80 m + 1.20 m = 2.50 m
Substituting the numbers into the formula, we find:
Final answer:
To calculate the gravitational force between the two spheres, we use Newton's law of gravitation. Substituting the given values into the formula will give us the magnitude of the gravitational force.
Explanation:
To calculate the magnitude of the gravitational force between two spheres, we can use Newton's law of gravitation, which states that the force is equal to the gravitational constant (G) multiplied by the product of the masses of the spheres and divided by the square of the distance between their centers. In this case, the gravitational force exerted by the first sphere on the second sphere can be calculated as:
F = (G * m1 * m2) / r^2
Substituting the given values, we get:
F = (6.67 × 10-11 N·m2/kg2)(65 kg)(87 kg) / (1.2 m)2
Calculating this expression will give us the magnitude of the gravitational force. The force exerted by the second sphere on the first sphere will have the same magnitude.
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Answers
Answer: THE OPTION IS E(ABOUT 200 MILLONS YEARS
Explanation:
). What's the force of gravity acting on the column of water?
A. 73,500 N
B. 102,900 N
C. 68,600 N
D. 110,700 N
Answers
Given:
liquid column is 7 meters and the area is 1.5 square meters (m2)
Required:
force of gravity
solution:
P = F/A where P is pressure, F is force and A is area
Since P = DgH where D is density, g is gravitational acceleration and H is height
DgH = F/A
F = ADgH
Let us assume D for water is 1000kg/m3
F = (1.5m2)(1000kg/m3)(9.8m/s2)(7m)
F = 102,900N
your answer is B. 102,900 N
i just took the test
Answers
=Fgd
= 225N * 15M
= 3375 Nm
Final answer:
Alejandra does 3375 Joules of work against gravity when she climbs to the ledge at the top of the climbing wall.
Explanation:
In order to calculate the work done against gravity, we can use the formula: Work = Force x Distance. The force of gravity can be calculated using the equation: Force = mass x acceleration due to gravity. Given that Alejandra weighs 225 newtons and the distance she climbs is 15 meters, we can plug these values into the formula to find the work done:
Work= (225 N) x (15 m) = 3375 Joules
Therefore, Alejandra does 3375 Joules of work against gravity when she climbs to the ledge at the top of the climbing wall.
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