Write expression using a positive exponent1. 5⁻ ²
2. -7 ⁻¹
3. t⁻⁶
4. n⁻²
write each expression as an expression using a negative exponent other than -1
5. 1/3⁴
6.1/9²
7.1/49
8.1/8

Answers

Answer 1

Answer: $1.\ \ 5^(-2)=(\frac15)^2=\frac1{5^2}\n\n 2.\ \ -7^(-1)=-(\frac17)^1=-\frac1{7^1}\n\n 3.\ \ t^(-6)=(\frac1t)^6=\frac1{t^6}\n\n 4.\ \ n^(-2)=(\frac1n)^2=\frac1{n^2}\n\n\n 5.\ \ (\frac13)^4=3^(-4)\n\n 6.\ \ (\frac19)^2 =(\frac1{3^2})^2 =(3^(-2))^2=3^(-4)\n\n 7.\ \ \frac1{49}=\frac1{7^2}=7^(-2)\n\n 8.\ \ \frac1{8}=\frac1{2^3}=2^(-3)$

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What is the GCF of 44j5k4 and 121j2k6?

4j3k2
4j2k4
11j3k2
11j2k4

Answers

Answer:

D) 11j2k4

Step-by-step explanation:

Simply find the prime factors of each term!

44 j5 k4

121 j2 k6

11 goes into 44 and 121. So, we can use 11!

2 works for j5 and j2, because of 10, so you would input j2.

4 works for both k4 and 46 because of 24, so k4.

11 j2 k4

Hope this helps! :)

Answer:

It's 11j2k4 the last one

Step-by-step explanation:

I took the test and got it right.

Look at the graph. Which of the following statements is reflected in the chart? A. Union soldiers were more likely to die of their wounds than Confederate soldiers. B. Soldiers in the Civil War were more likely to die of battle wounds than disease.
C. Soldiers in the Civil War were more likely to die of disease than wounds in battle. D. Union soldiers were less likely to die of wounds or disease than Confederate soldiers.
I think C or B

Answers

The answer is C. Disease has more deaths than battle wounds so it would be correct. A is kinda close but I don't think it's the answer. D is completely wrong cuz union had more deaths in both sections

Answer:

The answer is C.

Step-by-step explanation:

i took the test

Solve for x.

2x-4/10 = 2x/20

Answers

Refine:

$(2x-4)/(10)$

factor out common term 2 :

$(2(x-2))/(10)$

Cancel the common factor 2 :

$(x-2)/(5)$

Refine:

$(2x)/(20)$

$(x-2)/(5) = (x)/(10)$

find least common multiplier of 5 and 10

Multiply by LCM = 10

$(x-2)/(5) *10 = (x)/(10) *10$

$2(x-2)=x$

$2x - 4 = x$

Add 4 to both sides:

$2x-4+4 = x+4$

$2x = x + 4$

$2x - x = 4$

$x = 4$

hope this helps!

, _ . ’ make 11. Sam is the best running back on his football ' ' a . My ﬂ team Last-year he ran feet during his « ‘ .1. ten games How did he run for ‘ w _ w VJ ~ ; during I " 1 ,500 yards 2, 750 yards 3, 780 ya rods ‘ ' '3 ),403 ya

Answers

To find the answer, all you have to do is convert feet to yards.

1 foot = 0.33333333 or 1/3

0.33333333 (feet) × 4,215 (yards) = 1404.9999

The closest and reasonable answer is 1,403 yards.

A construction crew has just built a new road. They built the road at a rate of 7 kilometers per week. They built 8.75 kilometers of road. How many weeks did it take them?

Answers

7 kilometers per 1 week equals 8.75 kilometers per x weeks.

7 / 1 = 8.75 / x

7 = 8.75 / x

7x = 8.75

x = 8.75 / 7

x = 1.25

It took 1.25 weeks to build 8.75 kilometers of road.

Final answer:

The construction crew would need approximately 1.25 weeks to build 8.75 kilometers of road. This is calculated by dividing the total distance by the rate of construction.

Explanation:

To find out how many weeks it took the construction crew to build 8.75 kilometers of road, we need to divide the total distance (8.75 km) by the rate at which they built the road (7 km per week). So, the calculation will be 8.75 km ÷ 7 km/week.

This is a simple division problem. Using a calculator, you will find that 8.75 ÷ 7 equals approximately 1.25.

Therefore, the construction crew would need about 1.25 weeks to build 8.75 kilometers of road. Please note, this is an approximation, and actual times may vary.