Answer:
The answer is A) (-4,-1)
Step-by-step explanation:
You have to substitute!!! :)
A) (-4,-1):
y = 3 + x
-1 = 3 + -4
-1 = -1
YES
B) (2,-1):
y = 3 + x
-1 = 3 + 2
-1 = 5
NO
C) (2,-5):
y = 3 + x
-5 = 3 + 2
-5 = 5
NO
Answer:a
Step-by-step explanation:
If you substitue it in for a, you get 3-1=-4, which satisfies the equation.
Answer:
The equation that best represents the line that is parallel to 3x - 4y = 7 and passes through the point (-4, -2) is y = 3/4x + 1.
Step-by-step explanation:
3x - 4y = 7 and (-4, -2)
First, solve for y in the equation:
3x - 4y = 7
-4y = -3x + 7
4y = 3x - 7
y = 3/4x - 7/4
m = 3/4 (This will be the slope of the parallel line.) and (-4, -2)
Use the point-slope equation to find the equation that will best represent a parallel line:
y − y1 = m(x − x1)
y - -2 = 3/4(x - -4)
y + 2 = 3/4x + 3 (the 4s cancel out)
(3/4 x 4/1 = 3)
y = 3/4x + 1
The graph that I attached is what these two equations would look like graphed. I am not sure what you mean by two options, I'm sorry!
eHelp
Go online for Step-by-Step Solutions
Find the area of each figure. Round to the nearest tenth if
necessary.
(Example
(02 cm
12 cm
6 yd
4.5 cm
16 yd
8 yd
2 cm
show) 24 yd
5 cm
1 m.
15 c
15 m
Answer:
1. 64 cm²
2. 240 yard²
3. 85.13 cm²
4. 193.36 m²
Step-by-step explanation:
Ques 1: We are given two rectangle with dimensions,
Length = 12 cm, Width = 4.5 cm and Length = 5 cm, Width = 2 cm.
As, we know, Area of a rectangle = Length × Width
So, we have,
Area of 1st rectangle = 12 × 4.5 = 54 cm²
Area of 2nd rectangle = 5 × 2 = 10 cm²
Thus, the total area of the figure = 54 + 10 = 64 cm²
Ques 2: We are given a triangle and a rectangle with dimensions,
Triangle: Base = 24-12 = 12 yd and Height = 8 yd
As, Area of a triangle =
i.e. Area of the triangle =
i.e. Area of the triangle =
i.e. Area of the triangle = 48 yard²
Rectangle: Length = 24 yd, Width = 8 yd
As, we know, Area of a rectangle = Length × Width
i.e. Area of a rectangle = 24 × 8 = 192 yard²
So, the total area of the figure = 48 + 192 = 240 yard².
Ques 3: We are given a triangle and a semi-circle with dimensions,
Triangle: Base = 8 cm and Height = 15 cm
As, Area of a triangle =
i.e. Area of the triangle =
i.e. Area of the triangle =
i.e. Area of the triangle = 60 cm²
Semi-circle: Diameter = 8 cm implies Radius = 4 cm.
So, Area of the semi-circle =
i.e. Area of the semi-circle =
i.e. Area of the semi-circle =
i.e. Area of the semi-circle =
i.e. Area of the semi-circle = 25.13 cm²
Thus, the total area of the figure = 60 + 25.13 = 85.13 cm²
Ques 4: We are given a rectangle and a semi-circle of dimensions,
Rectangle: Length = 15 m, Width = 7 m.
As, we know, Area of a rectangle = Length × Width
i.e. Area of a rectangle = 15 × 7 = 105 m²
Semi-circle: Diameter = 15 m implies Radius = = 7.5 m
So, Area of the semi-circle =
i.e. Area of the semi-circle =
i.e. Area of the semi-circle =
i.e. Area of the semi-circle = 88.36 m²
Thus, the total area of the figure = 105 + 88.36 = 193.36 m²
The perimeter of the triangle is about 136
Firstly , let us learn about trigonometry in mathematics.
Suppose the ΔABC is a right triangle and ∠A is 90°.
There are several trigonometric identities that need to be recalled, i.e.
Let us now tackle the problem!
This problem is about Sine Rule.
First of all, we will calculate the ∠C :
∠A + ∠B + ∠C = 180°
72° + 16° + ∠C = 180°
∠C = 180° - 72° - 16°
∠C = 92°
Next, we will use the Sine Rule to find the length of the other side of the triangle.
Finally, we can find the perimeter of a triangle with the following formula
Grade: College
Subject: Mathematics
Chapter: Trigonometry
Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse
Answer:
136
Step-by-step explanation: