Parallel lines have the same a slope. Therefore if
k: y = 3x - 6 → slope = 3
and l: y = mx + b
l || k ⇔ m = 3
l: y = 3x + b
We have the point (-6, -7). Put the coordinates to the equation:
-7 = 3(-6) + b
-7 = -18 + b add 18 to both sides
11 = b → b = 11
A. -81
B. -9
C. 81
D. 9