MATHEMATICS MIDDLE SCHOOL

The height of a rectangular prism is found by dividing volume, V, by the base area, B. If the volume of the rectangular prism is represented by 6x2 – 2x + 8 and the base area is 2x – 4, which expression represents the height? 3x + 5 – 3x – 7 + 3x + 5 + 3x – 7 –

Answers

Answer 1

Answer:

Answer:

$(3x+5)+(28)/(2x-4)$

Step-by-step explanation:

Since,

The volume of a rectangular prism = Base area × Height,

Given,

Volume of the rectangular prism = $6x^2-2x+8$

Base area = 2x - 4

Let h be the height,

$\implies 6x^2-2x+8=(2x-4)h$

$\implies h = (6x^2-2x+8)/(2x-4)$

By long division ( shown below ),

$h=(3x+5)+(28)/(2x-4)$

Which is the required expression that represents the height.

Answer 2

Answer:

Answer:

$(3x+5) + (14)/(x-2)$

Step-by-step explanation:

We are given the following information in the question:

Volume of rectangular prism =

$6x^2 - 2x + 8$

Area of base of prism =

$2x -4$

Formula:

$\text{Volume of Prism} = \text{Area of base}* \text{Height of prism}\n\n\text{Height of prism} = \displaystyle\frac{\text{Volume of Prism} }{\text{Area of base}}$

Putting the values we, get,

$\text{Height of prism} = \displaystyle(6x^2 - 2x +8)/(2x-4) = (2(3x^2-x+4))/(2(x-2))= (3x+5) + (14)/(x-2)$

Hence, the height of the prism is given by the expression $(3x+5) + (14)/(x-2)$

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What is the degree of the polynomial? 4m the the 2nd power - 3m to the 6th power + 5m to the 4th power

Answers

It is to the 12th degree

Answer:

Degree of polynomial = 6

Brennan ate 2 1/4 apples.Then he ate another 1 2/4 apples the next day.How many apples did Brennan eat altogether?Write in simplest.

Answers

1. Convert the mixed fractions to a decimal. 2 1/4 is 2.25 1 2/4 is 1.5 2. Add them up. 3. 3.75 as a decimal or 3 3/4 as a mixed fraction or 15/4 as a improper fraction.

Q(x)=4x^2-1 find Q(-7)

Answers

$q( - 7) = 4x {}^(2) - 1$
so
$4( - 7) {}^(2) - 1$
195

$Solution, \mathrm{Isolate}\:x\:\mathrm{for}\:If\left(I,\:x\right)Q\left(x\right)=4x^2-1:\quad x=(√(f\left(I,\:x\right)Q\left(x\right)I+1))/(2),\:x=-(√(f\left(I,\:x\right)Q\left(x\right)I+1))/(2)$

$Steps: If\left(I,\:x\right)Q\left(x\right)=4x^2-1$

$\mathrm{Switch\:sides}, 4x^2-1=If\left(I,\:x\right)Q\left(x\right)$

$\mathrm{Add\:}1\mathrm{\:to\:both\:sides}, 4x^2-1+1=If\left(I,\:x\right)Q\left(x\right)+1$

$\mathrm{Simplify}, 4x^2=If\left(I,\:x\right)Q\left(x\right)+1$

$\mathrm{Divide\:both\:sides\:by\:}4, (4x^2)/(4)=(If\left(I,\:x\right)Q\left(x\right))/(4)+(1)/(4)$

$\mathrm{Simplify}, x^2=(f\left(I,\:x\right)Q\left(x\right)I+1)/(4)$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=√(f\left(a\right)),\:\:-√(f\left(a\right)), x=\sqrt{(f\left(I,\:x\right)Q\left(x\right)I+1)/(4)},\:x=-\sqrt{(f\left(I,\:x\right)Q\left(x\right)I+1)/(4)},\sqrt{(f\left(I,\:x\right)Q\left(x\right)I+1)/(4)}=(√(f\left(I,\:x\right)Q\left(x\right)I+1))/(2),-\sqrt{(f\left(I,\:x\right)Q\left(x\right)I+1)/(4)}=-(√(f\left(I,\:x\right)Q\left(x\right)I+1))/(2)$

The correct answer is $x=(√(f\left(I,\:x\right)Q\left(x\right)I+1))/(2),\:x=-(√(f\left(I,\:x\right)Q\left(x\right)I+1))/(2)$

the perimeter of a rectangle is 32 centimeters. The length is 1 cm more than twice the width. Find the dimensions of the rectangle.

Answers

Answer: length = 11cm , width = 5cm

Step-by-step explanation:

The formula for calculating the perimeter of a rectangle is given by :

P = 2 ( L + w )

The length is 1 cm more than twice the width implies:

L = 1 + 2w

substituting into the formula , we have

32 = 2 ( 1 + 2w + w )

32 = 2 ( 1 + 3w)

32 = 2 + 6w

32 - 2 = 6w

30 = 6w

Therefore :

w = 5

then

L = 1 + 2w

L = 1 + 2 ( 5 )

L = 1 + 10

L = 11

Therefore , the length is 11 cm and the width is 5cm

Could you answer all the ones

Answers

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Answers

Answer: 160,161,178

Step-by-step explanation: first it adds 17 to the equation then adds 1 repeat this process and you get these answers.

Answer:

Step-by-step explanation:

286,287,574

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