Answer: the marble will remain in place at a constant velocity of zero
Explanation:
Newton's first law states that a body at rest will remain at rest, and a body in motion will remain in motion in a straight line at a constant velocityunless acted upon by an outside force
Answer: The impulse delivered to the object is 33 N • s.
Explanation: Impulse = Change in momentum
The momentum of an object is calculated by multiplying its mass by its velocity:
Momentum = Mass x Velocity
Given:
Mass of the object = 1.5 kg
Initial velocity = +15 m/s
Final velocity = +22 m/s
Time interval = 3.5 seconds
First, we need to calculate the change in momentum:
Change in momentum = Final momentum - Initial momentum
To find the initial momentum, we multiply the mass by the initial velocity:
Initial momentum = Mass x Initial velocity
Initial momentum = 1.5 kg x 15 m/s
To find the final momentum, we multiply the mass by the final velocity:
Final momentum = Mass x Final velocity
Final momentum = 1.5 kg x 22 m/s
Now, we can calculate the change in momentum:
Change in momentum = Final momentum - Initial momentum
Change in momentum = (1.5 kg x 22 m/s) - (1.5 kg x 15 m/s)
Simplifying the equation:
Change in momentum = 33 kg m/s
Finally, we have found the change in momentum, which is equal to the impulse delivered to the object. Therefore, the impulse delivered to the object is 33 N • s.
Answer:
11 Ns
Explanation:
Impulse = change in momentum
J = Δp
J = mΔv
J = (1.5 kg) (22 m/s − 15 m/s)
J = 10.5 kg m/s
Rounded to two significant figures, the impulse is 11 Ns.
(b Can this plane land on a runaway that is only 0.800 km long?
shown work pls will reward alot of points
Answer:
a) t = 20 s, b) x = 1000 m, As the runway is only 800 m long, the plane cannot land at this distance
Explanation:
This is a kinematics exercise
a) in minimum time to stop,
v = vo + at
v = 0
t = -v0 / a
we calculate
t = -100 / (5.00)
t = 20 s
b) Let's find the length you need to stop
v² = vo² + 2 a x
x = -v0 ^ 2 / 2a
x = - 100² / 2 (-5.00)
x = 1000 m
As the runway is only 800 m long, the plane cannot land at this distance.