The volume of the given pyramid with a squarebase whose side measures 6 inches and the altitude of the pyramid measures 12 inches is 144 cubic inches. The value is obtained by applying the formula for the volume of the pyramid as .
The volume of the pyramid is given by the formula:
Where,
is the area of the base of the pyramid and
h is the height or altitude of the pyramid
As shown in the diagram,
The pyramid has a squarebase whose side measures 6 inches and the altitude of the pyramid is 12 inches
Thus,
Area of the square base,
⇒
⇒ sq. inches
Height of the pyramid h = 12 inches
On substituting the values in the formula,
⇒ × 36 × 12
⇒ 4 × 36
⇒ 144 cubic inches
Therefore, the volume of the given pyramid is 144 cubic inches.
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Answer:
144 in³
Step-by-step explanation:
The volume of a pyramid of base area A and height h is
V = (1/3)(A)(h).
Here,
V = (1/3)(6 in)²(12 in) = 144 in³
B. -2y2 - 11y + 10
C. -2y2 + 11y - 10
D. 2y2 + 11y - 10
Answer:
D..
Step-by-step explanation:
Given:
We need to reduce by
Solution:
To reduce the equation means we need to subtract the one equation from other.
First we will arrange the equation n proper format we get;
⇒ equation 1
Also Arranging other equation we get;
⇒ equation 2
Now we will subtract equation 2 from equation 1 we get;
Now Applying distributive property for the sign we get;
Now Arranging the like terms we get;
Hence the reduce form of the given equation is .
Answer:
2y^2 + 11y - 10
The answer is D.
6 + (-8)
-6 + 8
6 + 8
-6 + (-8)
Answer:
Step-by-step explanation:
Answer:
D is the answer
Step-by-step explanation:
4*2 is equal to 8 so it would be 8x 4*3y is equal to 12y